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emmasim [6.3K]
3 years ago
14

A student gives a brief push to a block of dry ice. A moment later, the block moves across a very smooth surface at a constant s

peed. When drawing the free body diagram for the block of dry ice moving at a constant speed, the forces that should be included are: (select all that apply)
a. gravity
b. force
c. force of friction
d. normal force
Physics
2 answers:
Monica [59]3 years ago
7 0
Hey There,

Question: "<span>A student gives a brief push to a block of dry ice. A moment later, the block moves across a very smooth surface at a constant speed. When drawing the free body diagram for the block of dry ice moving at a constant speed, the forces that should be included are: (select all that apply)"

Answer: C. Force Of Friction
              B. Force

If This Helps May I Have Brainliest?</span>
mel-nik [20]3 years ago
7 0
Hey there,

Your question states: <span>A student gives a brief push to a block of dry ice. A moment later, the block moves across a very smooth surface at a constant speed. When drawing the free body diagram for the block of dry ice moving at a constant speed, the forces that should be included are: (select all that apply)

Your correct answer would be "force of friction" and also just plain "force". The reason why it would just be "force" would be because the student gave a little push to the block of dry ice. This would be the motion of force. Now, the fact that the block continued to move at a constant speed would be because it had a "force of friction" which means that there is a substance that would attract the block of dry ice. That is why the "force of friction" would be your answer. Now, GRAVITY  would be involved in this case, the block of ice is already on the ground, this gravity would NOT be your answer.

Hope this helps.

~ Nerdy Astute 

</span>
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Answer:

central nervous system

peripheral nervous system

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The nervous system has two main parts: The central nervous system is made up of the brain and spinal cord. The peripheral nervous system is made up of nerves that branch off from the spinal cord and extend to all parts of the body.Oct 1, 2018

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Manuel is holding a 5 kg box. How much force us the box exerting on him? in what direction
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It will be 49 Newtons of force in the down direction. To find the force in newtons, you multiply the mass (5 kg) by the gravity (which if 9.8). 
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The moons of Mars, Phobos (Fear) and Deimos (Terror), are very close to the planet compared to
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T=(Rp/Rd)^3/2

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The electrons in the beam of a television tube have an energy of 19.0 keV. The tube is oriented so that the electrons move horiz
igomit [66]

Answer:

The direction is due south

Explanation:

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     The energy of the electron is E = 19.0keV = 19.0 *10^3 eV

      The earths magnetic field is B = 42.3 \muT = 42.3 *10^{-6} T

     

Generally the force on the electron is perpendicular to the velocity of the elecrton and the magnetic field and this is mathematically reresented as

          \= F = q (\= v * \=B)

On the first uploaded image is an  illustration of the movement of the electron

    Looking at the diagram  we can see that in terms of direction  the magnetic force  is

             \= F  =q(\=v * \= B)= -( -\r i * - \r k)

                = -(- (\r i * \r k))

generally  i cross k = -j

      so the equation above becomes

             \= F = -(-(- \r j))

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3 0
3 years ago
The density of a block of wood is 694 kg/m3. Its mass is 689 g. We tie the block to the bottom of a swimming pool using a single
Serhud [2]

Answer:

<em>The tension in the string = 2.065 N</em>

Explanation:

From Archimedes principle,

R.d = density of the wood block/density of water = weight of the wood block/Upthrust of the wood block in water.

R.d = D₁/D₂ = W/U

W/U =D₁/D₂.................................. Equation 1

Where W = weight of the wood block, U = upthrust of the wood block in water, D₁ = Density of the wood block, D₂ = Density of water.

Making U the subject of the equation,

U = WD₂/D₁........................... Equation 2

Given: W =  mg = (689/1000)9.8 = 6.75 N,  D₁ = 694 kg/m³, D₂ = 1000 kg/m³.

Substituting these values into equation 2,

U = 6.75(694)/1000

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U = 4.685 N.

Note: Three forces act on the wood block in the pool. and they are

(i) The weight(W) acting downs

(ii) The upthrust (U) acting upwards,

(iii) The Tension (T) in the string, acting upwards.

Thus,

W = U+T

T = W - U ................................. Equation 3

Where W = 6.75 N, U = 4.685 N

T = 6.75 - 4.685

T = 2.065 N.

T = 2.065 N

<em>Thus the tension in the string = 2.065 N</em>

7 0
2 years ago
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