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Serjik [45]
3 years ago
5

The relatively high boiling point of water is due to water having

Chemistry
1 answer:
Marina86 [1]3 years ago
7 0
The correct answer is option 1. Water  has a relatively high boiling point due to the presence of hydrogen bonding between atoms. Hydrogen bonding is said to be the most powerful or strongest intermolecular force as compared to others therefore it has a higher boiling point because higher energy is needed to break this bond.
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When a chemical reaction occurs what happens to the properties of the substance
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Answer:

the molecules in the reactants interact to form new substances.

Explanation:

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Which list consists of elements that have the most similar chemical properties?
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Why is the state of matter a physical<br> property of matter?
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3 years ago
Arrange the following aqueous solutions in order of increasing boiling point temperature (lowest to highest temperature, with 1
Elanso [62]

Answer:

0.20 m glucose < 0.40 m NaCl < 0.30 m BaCl2 < 0.50 m Na2SO4.

Explanation:

Step 1: Data given

ΔT = i*Kb*m

⇒ΔT = the boiling point elevation =  Shows how much the boiling point increases

⇒i = the van't Hoff factor: Says in how many particles the compound will dissociate

⇒ Since all are aqueous solutions Kb for all solutions is the same (0.512 °C/m)

⇒m = the molality

Step 2:

0.20 m glucose

ΔT = i*Kb*m

⇒ΔT = the boiling point elevation = TO BE DETERMINED

⇒i = the van't Hoff factor for glucose = 1

⇒ Kb = 0.512 °C/m

⇒m = 0.20 m

ΔT = 1*0.512 * 0.20

<u>ΔT = 0.1024 °C</u>

0.30 m BaCl2

ΔT = i*Kb*m

⇒ΔT = the boiling point elevation = TO BE DETERMINED

⇒i = the van't Hoff factor for BaCl2 = Ba^2+ + 2Cl- : i = 3

⇒ Kb = 0.512 °C/m

⇒m = 0.30 m

ΔT = 3*0.512 * 0.30

<u>ΔT = 0.4608 °C</u>

0.40 m NaCl

ΔT = i*Kb*m

⇒ΔT = the boiling point elevation = TO BE DETERMINED

⇒i = the van't Hoff factor for NaCl = Na+ + Cl- : i = 2

⇒ Kb = 0.512 °C/m

⇒m = 0.40 m

ΔT = 2*0.512 * 0.40

<u>ΔT = 0.4096 °C</u>

0.50 m Na2SO4.

ΔT = i*Kb*m

⇒ΔT = the boiling point elevation = TO BE DETERMINED

⇒i = the van't Hoff factor for Na2SO4 = 2Na+ + SO4^2- : i =3

⇒ Kb = 0.512 °C/m

⇒m = 0.50 m

ΔT = 3*0.512 * 0.50

<u>ΔT = 0.768 °C</u>

0.20 m glucose < 0.40 m NaCl < 0.30 m BaCl2 < 0.50 m Na2SO4.

8 0
3 years ago
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