Question

Factor the expression below. x2 - 6x + 9 A. 3(x2 - 2x + 3) B. (x - 3)(x + 3) C. (x + 3)(x + 3) D. (x - 3)(x - 3)

Answer 1

For this case we must factor the following quadratic expression:

$x ^ 2-6x + 9$

To factor, we must find two numbers that when multiplied give as result +9 and when added or subtracted give as result -6.

These numbers are:

-3 and -3

$-3-3 = -6\\-3 * (- 3) = + 9$

So, we have:

$(x-3) (x-3)$

ANswer:

Option D

Answer 2

Answer:

D. (x - 3)(x - 3)

Step-by-step explanation:

We are given the following expression and we are to factorize it:

$x^2-6x+9$

Finding factors of positive 9 such that when added they give a result of -6.

$x ^ 2 - 6 x + 9$

$x ^ 2 - 3 x - 3 x + 9$

Factorizing them to get:

$x ( x - 3 ) - 3 ( x - 3 )$

$( x - 3 ) ( x - 3 )$