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2 years ago

How did you use QPOE?

Chemistry

1 answer:

Jlenok [28]2 years ago

8 0

QPOE Files

The x-ray data are stored in QPOE files (Quick Position-Ordered Events, *.qp) rather than image arrays. These are lists of photons identified by several quantities, including the position on the detector, pulse height, and arrival time. Note that, unlike IRAF images, QPOE files have no associated header file, and are always stored in the current directory, unless explicitly specified otherwise. Non-PROS IRAF tasks can also access QPOE data files in place of image arrays.

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What molecules must the plant take in so the process of photosynthesis can occur

lilavasa [31]

Answer:

Glucose molecules

Explanation:

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2 years ago

Estimate the standard internal energy of formation of liquid methyl acetate (methyl ethanoate, ch3cooch3) at 298 k from its stan

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solution:

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2 years ago

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Which term names elements that are usually shiny and good conductors of heat and electricity?

Sonbull [250]

Elements that are usually shiny and good conductors of heat and electricity are metals.

<h3>What are conductors?</h3>

The conductors are the metal or non metal elements which allow heat and electricity to easily pass through them.

Metals are elements with good conductivity of electric current and heat. Metals have lustre characteristics. They are shiny and bendable just like copper wire, which is a metal.

Hence, elements that are usually shiny and good conductors of heat and electricity are metals.

Learn more about conductors.

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1 year ago

Is aluminum foil a mixture or a pure substance?

Naddik [55]

Pure Substance.........

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2 years ago

g A laboratory analysis of an unknown compound found the following composition: C 75.68% ; H 8.80% ; O 15.52%. What is the empir

sammy [17]

Answer:

THE EMPIRICAL FORMULA FOR THE UNKNOWN COMPOUND IS C7H9O

Explanation:

The empirical formula for the unknown compound can be obtained by following the processes below:

1 . Write out the percentage composition of the individual elements in the compound

C = 75.68 %

H = 8.80 %

O = 15.52 %

2. Divide the percentage composition by the atomic masses of the elements

C = 75 .68 / 12 = 6.3066

H = 8.80 / 1 = 8.8000

O = 15.52 / 16 = 0.9700

3. Divide the individual results by the lowest values

C = 6.3066 / 0.9700 = 6.5016

H = 8.8000 / 0.9700 = 9.0722

O = 0.9700 / 0.9700 = 1

4. Round up the values to the whole number

C = 7

H = 9

O = 1

5 Write out the empirical formula for the compound

C7H90

In conclusion, the empirical formula for the unknown compound is therefore C7H9O

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2 years ago

How did you use QPOE?​

How did you use QPOE?