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lys-0071 [83]
3 years ago
8

the experimental yield of a compound is 30 g and the true yield is 40 g what is the percentage error in calculating the yield

Chemistry
1 answer:
AleksAgata [21]3 years ago
3 0

Answer:

25%.

Explanation:

The following data were obtained from the question:

Experimental yield = 30 g

Actual yield = 40 g

Percentage error =..?

Thus, we can calculate the percentage error as follow:

Percentage error = |Experimental – Actual | / Actual × 100

Percentage error = |30 – 40|/40 × 100

Percentage error = 10/40 × 100

Percentage error = 25 %

Therefore, the percentage error in calculating the yield is 25%

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White phosphorus melts and then vaporizes at high temperatures. The gas effuses at a rate that is 0.404 times that of neon in th
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White phosphorus melts and then vaporizes at high temperatures. The gas effuses at a rate that is 0.404 times that of neon in the same apparatus under the same conditions-There are 4 atoms of P in the molecule

Explanation:

Ar=30,97g/mol

R_{Px/R_Ne}=\sqrt{Mr(Ne)/Mr(Px)}=0,404

0,404=\sqrt{20,18/30,97*x}

0,404^{2}=20,18/30,97*x

X=20,18/30,97*0,163

X=4

There are 4 atoms of P in the molecule

White phosphorus melts and then vaporizes at high temperatures. The gas effuses at a rate that is 0.404 times that of neon in the same apparatus under the same conditions-There are 4 atoms of P in the molecule

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3 years ago
What is the main purpose of using NaOH in the saponification reaction . NaOH works as the catalyst b. NaOH solution is the solve
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Answer:

C. NaOH acts as a reactant in the reaction

Explanation:

Because during the saponification process, Na+ replaces the H+ in the fatty acid been used for the saponification process

7 0
4 years ago
For each of the following sublevels, give the n and l values and the number of orbitals: (a) 6g; (b) 4s; (c) 3d.
olya-2409 [2.1K]

Answer:

(a) 6g. Shell 6, n = 6. Subshell g, l = 4. Number of orbitals in sublevel = 9

(b) 4s. Shell 4, n = 4. Subshell s, l = 0. Number of orbitals in sublevel = 1

(c) 3d. Shell 3, n = 3. Subshell d, l = 2. Number of orbitals in sublevel = 5

Explanation:

The rules for electron quantum numbers are:

1. Shell number, 1 ≤ n, n = 1, 2, 3...

2. Subshell number, 0 ≤ l ≤ n − 1, orbital s - 0, p - 1, d - 2, f - 3

3. Orbital energy shift, -l ≤ ml ≤ l

4. Spin, either -1/2 or +1/2

So,

(a) 6g. Shell 6, n = 6. Subshell g, l = 4. Number of orbitals in sublevel = 2l+1 = 9

(b) 4s. Shell 4, n = 4. Subshell s, l = 0. Number of orbitals in sublevel = 2l+1 = 1

(c) 3d. Shell 3, n = 3. Subshell d, l = 2. Number of orbitals in sublevel = 2l+1 = 5

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