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lys-0071 [83]
3 years ago
8

the experimental yield of a compound is 30 g and the true yield is 40 g what is the percentage error in calculating the yield

Chemistry
1 answer:
AleksAgata [21]3 years ago
3 0

Answer:

25%.

Explanation:

The following data were obtained from the question:

Experimental yield = 30 g

Actual yield = 40 g

Percentage error =..?

Thus, we can calculate the percentage error as follow:

Percentage error = |Experimental – Actual | / Actual × 100

Percentage error = |30 – 40|/40 × 100

Percentage error = 10/40 × 100

Percentage error = 25 %

Therefore, the percentage error in calculating the yield is 25%

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    <u><em>Explanation</em></u>

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therefore  since  there 1 atom  of C  in product side there  must be 1 atom of C  in reactant  side.

In addition  there is 2 H atom in product  side  which should be the  same  in reactant side.  

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Molecular formula  calculation

[CH2}n= 84 g/mol

[12+ (1x2)] n = 84 g/mol

14 n =  84 g/mol

n = 6

multiply the  each subscript  in CH2  by  6

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