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lys-0071 [83]
3 years ago
8

the experimental yield of a compound is 30 g and the true yield is 40 g what is the percentage error in calculating the yield

Chemistry
1 answer:
AleksAgata [21]3 years ago
3 0

Answer:

25%.

Explanation:

The following data were obtained from the question:

Experimental yield = 30 g

Actual yield = 40 g

Percentage error =..?

Thus, we can calculate the percentage error as follow:

Percentage error = |Experimental – Actual | / Actual × 100

Percentage error = |30 – 40|/40 × 100

Percentage error = 10/40 × 100

Percentage error = 25 %

Therefore, the percentage error in calculating the yield is 25%

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Which object is a good conductor of heat and electricity?
Alex

Answer:

C

Explanation:

Metals are good conductors of heat

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2 years ago
How many moles of methane are produced when 85.1 moles of carbon dioxide gas react with excess hydrogen gas?
tino4ka555 [31]

Taking into account the reaction stoichiometry, 340.0 moles  of methane are produced when 85.1 moles of carbon dioxide gas react with excess hydrogen gas

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

CO₂ + 4 H₄  → CH₄ + 2 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • CO₂: 1 mole
  • H₄: 4 moles  
  • CH₄: 1 mole
  • H₂O: 2 moles

<h3>Moles of CH₄ formed</h3>

The following rule of three can be applied: if by reaction stoichiometry 1 mole of CO₂ form 4 moles of CH₄, 85.1 moles of CO₂ form how many moles of CH₄?

moles of CH_{4} =\frac{85.1 moles of CO_{2}x4 moles of CH_{4} }{1 moles of CO_{2}}

<u><em>moles of CH₄= 340.4 moles</em></u>

Then, 340.0 moles  of methane are produced when 85.1 moles of carbon dioxide gas react with excess hydrogen gas

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

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6 0
1 year ago
2. Which of the following is true about the total number of reactants and the total number of
Soloha48 [4]

9 moles of reactants chemically change into 11 moles of product.

Explanation:

In the reaction above, 9 moles of reactants chemically change into 11 mole of products. The coefficients in a reaction is the number of moles of the reacting atoms .

  • For example 8O₂ depicts 8 moles of two oxygen atoms.
  • The number of moles  is a unit for quantifying particles.
  • You can liken it to a dozen, gross or a score.
  • Since a mole of a substance contains avogadro number of particles. We can relate the number of moles to other parameters.

Learn more:

Moles brainly.com/question/2272966

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8 0
2 years ago
Read 2 more answers
What volume of 7.68 M NaOH (aq) will neutralize 1.15 L of 2.35 M H2SO4 (aq) ?
aleksklad [387]

Answer:

hmm lemme think bur it will take a while

8 0
2 years ago
How many hydrogen atoms are in 5.80 mol of ammonium sulfide
IRINA_888 [86]

Moles of ammonium sulfide =  5.80 mol

The formula of ammonium sulfide is (NH₄)₂S

So each molecule of ammonium sulfide has (4 x 2)  or 8 atoms of H

One mole of ammonium sulfide has 8 moles of H

5.80 mol of ammonium sulfide has (8 x 5.8) or 46.4 moles of H

As per the definition of Avogadro's number, 1 mole = 6.022 x 10²³ atoms

46.4 moles of H x (6.022 x 10²³ atoms/ 1 mole of H)

= 2.8 x 10²⁵ H atoms

Therefore, 2.8 x 10²⁵ H atoms are in 5.80 mol of ammonium sulfide.

5 0
3 years ago
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