Answer:
1)chest
2)deltoid
3)bicep
4)abs
5)quadriceps
6)lats
7)triceps
8)glutes
9)calves
10)hamstring
11)trapezuis
Explanation:
the explanation is the picture
good luck :)
hopefully, this helps
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Answer:
the maximum frequency observed is 2.0044 10⁶ Hz
Explanation:
This is a Doppler effect exercise. Where the emitter is still and the receiver is mobile, therefore the expression that describes the process is
f ’=
the + sign is used when the observer approaches the source
typical speeds of a baby's heart stop are around 200 m / min
let's reduce to SI units
v₀ = 200 m / min (1 min / 60 s) = 3.33 m / s
let's calculate
f ’= 2 10⁶ ()
f ’= 2.0044 10⁶ Hz
f ’= 1,9956 10⁶ Hz
therefore the maximum frequency observed is 2.0044 10⁶ Hz
Answer:
B.The force of friction between the block and surface will decrease.
Explanation:
The force of friction is given by
where is the coefficient of friction and is the normal force.
When the student pulls on the block with force at an angle , the normal force on the block becomes
and hence the frictional force becomes
.
Now, as we increase , increases which as a result decreases the normal force , which also means the frictional force decreases; Hence choice B stands true.
<em>P.S: Choice D is tempting but incorrect since the weight </em><em> is independent of the external forces on the block. </em>
Answer:
a= -1.01m/s^2
Explanation:
A) We define all the variables that are given,
In this way
Acceleration = a
We obtain the Normal assuming 5% of the potato reading scale, so
We add forces to reach equilibrium, and you get
** The notation of the symbols is done according to the notation of the graph
So,
B) When making pressure it is understood that the shape takes the perpendicular direction of the direction of the force that is performed. If the pressure remains constant, the scale will also increase in its measurement.
Answer:
Part a)
Part b)
Explanation:
Let the length of the rod at 0 degree Celsius is given as Lo
now we have
now we know that
= Length of rod at zero degree C
Part a)
now we have
now we have
Part b)
length of the rod is 6.3689 cm
now we have