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kenny6666 [7]
3 years ago
10

Ben walks 500 meters from his house to the corner store. He then walks back toward his house but stops to talk to a neighbor whe

n he is 200 meters from the corner store. If it takes Ben 910 seconds from the time he leaves his house until he stops to talk to his neighbor, what is his average velocity?
Physics
2 answers:
spin [16.1K]3 years ago
7 0
Average velocity =

      (displacement) / (time for the displacement)
and
      (direction of the displacement) .

Displacement =

      (distance from the start-point to the end-point)
and
      (direction from the start-point to the end-point)   .

When Ben is 200 meters from the corner store,
he is (500 - 200) = 300 meters from his house.

His displacement is

         300 meters in the direction
                             from his house to the neighbor .


His average velocity is

         (300/910) =  0.33 meters per second, in the
                               direction from his house to the neighbor .


Kay [80]3 years ago
7 0

Answer:

0.3 m/s

Explanation:

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Answer:

Velocity (m/s) over time (s) graph

Velocity (m/s) over time (s) graph

We could write out our average acceleration as:

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What this formula is telling us is that if we know the acceleration of an object, and the ... we can plug in our acceleration of 12.5 m/s2 for a, and 4 seconds for t.

Velocity (m/s) over time (s) graph

Velocity (m/s) over time (s) graph

We could write out our average acceleration as:

a = Δv/ Δta=Δv/Δta, equals, Δ, v, slash, Δ, t

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a = 15 m/s / 0.2 seconds

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3 years ago
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