Answer : (C) Hafnium is the most likely identity of the given substance.
Solution : Given,
Mass of given substance (m) = 46.9 g
Volume of given substance (V) = 3.5
First, find the Density of given substance.
Formula used :
Now,put all the values in this formula, we get
= 13.4 g/
So, we conclude that the density of given substance (13.4 g/) is approximately equal to the density of Mercury and Hafnium (13.53 and 13.31 g/ respectively).
According to the question the substance is solid at room temperature but Mercury is liquid at room temperature. So, Mercury is not identical to the given substance.
Another element i.e, Hafnium is the element whose density is approximately equal to the given substance and also solid at room temperature. And we know that the melting point of solid is high.
So, Hafnium is the most likely element which is the identity of the given substance.
Answer:
A reduction-oxidation (redox) reaction will occur.
Chlorine gas (Cl2) will accept electrons to form Cl- ions.
The Iron(II) ions (Fe2+) will lose electrons to form Fe3+ ions. (Iron (III) ions)
Fe2+ ions are green, while Fe3+ ions are yellow,
so the observation will be the solution turning from green to yellow.
Your drawing looks so good :p
Elements in the same group have the same amount of electrons.
Elements in the same period have the same amount of atomic orbits.
Hope this helps!
Answer:
I think it is B
Explanation:
because the others don't look right