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Zina [86]
3 years ago
14

Can you help.me this above question. ..​

Chemistry
1 answer:
matrenka [14]3 years ago
4 0

Answer:

Explanation:

Chlorine halogen

Non-metal oxygen

Metal calcium

Ethyne C2H2

Ethene C2H4

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Assuming 100% dissociation, calculate the freezing point and boiling point of 1.22 m SnCl₄(aq). Constants may be found here.
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Answer:

T° freezing solution → -11.3°C

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Explanation:

Assuming 100 % dissociation, we must find the i, Van't Hoff factor which means "the ions that are dissolved in solution"

This salt dissociates as this:

SnCl₄ (aq)  →   1Sn⁴⁺ (aq)  +   4Cl⁻  (aq)   (so i =5)

The formula for the colligative property of freezing point depression and boiling point elevation are:

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Freezing point depression:

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T° freezing solution = - (1.86°C/m . 1.22 m . 5) → -11.3°C

Boiling point elevation:

T° boiling solution - 100°C = 0.512 °C/m . 1.22 m . 5

T° boiling solution = (0.512 °C/m . 1.22 m . 5) + 100°C → 103.1 °C

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