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2 years ago

Choose the substance with the higher entropy in each pair. Assume constant temperature, except in part (5)

Chemistry

1 answer:

Nataly [62]2 years ago

3 0

Answer:

I) 1 mol of SO3(g)

2) 1 mol of CO2(g)

3) 3 mol of O2(g)

4) 1 mol of KBr(aq)

5) Seawater at 23°C

6) 1 mol of CCl4(g)

Explanation:

In molecules having greater numbers of atoms, there is an increase the number of ways by which the molecule vibrates thereby leading to a higher number of possible microstates and overall increase in entropy of the system. Hence, 1 mol of SO3(g) has a higher entropy than 1 mol of SO2.

Gases have a higher entropy than liquids and liquids have a higher entropy than gases.

Also, the greater the molecular weight of a molecule, the higher the entropy. Higher number of moles of a gas as well as the increase in temperature of a substance are also factors that lead to higher entropy.

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What is the answer to this chemistry question?

olga_2 [115]

Answer:

The answer to your question is remplacement double

Explanation:

Data

Lead (II) nitrate = Pb(NO₃)₂

Potassium iodide = KI

Process

1.- Write the balanced chemical reaction

Pb(NO₃)₂ + 2KI ⇒ PbI₂ + 2KNO₃

2.- Conclusion

This is a remplacement double reaction because there are two reactants that interchange cations and the products are a combination of the reactants.

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3 years ago

Photosynthesis stores energy. True or False

postnew [5]

True if im wrong u can take away my points

6 0

3 years ago

Read 2 more answers

Plz help guys ASAP! <br> Thanks in advance

MariettaO [177]

Answer:

3.6 moles

Explanation:

The balanced equation for the reaction is given below:

N₂ + 3H₂ —> 2NH₃

From the balanced equation above,

1 mole of N₂ reacted with 3 moles of H₂ to produce 2 moles NH₃.

Next, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above,

1 mole of N₂ reacted with 3 moles of H₂.

Therefore, 3.2 moles of N₂ will react with = 3.2 × 3 = 9.6 moles of H₂.

From the calculation made above, we can see that it will take a higher amount (i.e 9.6 moles) of H₂ than what was given (i.e 5.4 moles) to react completely with 3.2 moles of N₂.

Therefore, H₂ is the limiting reactant and N₂ is the excess reactant.

Finally, we the greatest quantity of ammonia, NH₃ produced from the reaction.

In this case, the limiting reactant will be use because all of it is consumed in the reaction.

The limiting reactant is H₂ and greatest quantity of ammonia, NH₃ produced can be obtained as follow:

From the balanced equation above,

3 moles of H₂ reacted to produce 2 moles NH₃.

Therefore, 5.4 of H₂ will react to produce = (5.4 × 2)/3 = 3.6 moles of NH₃

Thus, the greatest quantity of ammonia, NH₃ produced from the reaction is 3.6 moles

4 0

3 years ago

What is the frequency of a wave with a wavelength of 6.40x10^4 meters?

yKpoI14uk [10]

Answer:

frequency = 0.47×10⁴ Hz

Explanation:

Given data:

Wavelength of wave = 6.4× 10⁴ m

Frequency of wave = ?

Solution:

Formula:

Speed of wave = wavelength × frequency

Speed of wave = 3 × 10⁸ m/s

Now we will put the values in formula.

3 × 10⁸ m/s = 6.4× 10⁴ m × frequency

frequency = 3 × 10⁸ m/s / 6.4× 10⁴ m

frequency = 0.47×10⁴ /s

s⁻¹ = Hz

frequency = 0.47×10⁴ Hz

Thus the wave with wavelength of 6.4× 10⁴ m have 0.47×10⁴ Hz frequency.

4 0

3 years ago

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How many moles of sodium carbonate are contained by 57.3g of sodium carbonate

Lady_Fox [76]

Answer:

$\boxed {\boxed {\sf 0.541 \ mol \ Na_2CO_3}}$

Explanation:

We are asked to find how many moles of sodium carbonate are in 57.3 grams of the substance.

Carbonate is CO₃ and has an oxidation number of -2. Sodium is Na and has an oxidation number of +1. There must be 2 moles of sodium so the charge of the sodium balances the charge of the carbonate. The formula is Na₂CO₃.

We will convert grams to moles using the molar mass or the mass of 1 mole of a substance. They are found on the Periodic Table as the atomic masses, but the units are grams per mole instead of atomic mass units. Look up the molar masses of the individual elements.

Na: 22.9897693 g/mol
C: 12.011 g/mol
O: 15.999 g/mol

Remember the formula contains subscripts. There are multiple moles of some elements in 1 mole of the compound. We multiply the element's molar mass by the subscript after it, then add everything together.

Na₂ = 22.9897693 * 2= 45.9795386 g/mol
O₃ = 15.999 * 3= 47.997 g/mol
Na₂CO₃= 45.9795386 + 12.011 + 47.997 =105.9875386 g/mol

We will convert using dimensional analysis. Set up a ratio using the molar mass.

$\frac {105.9875386 \ g \ Na_2CO_3}{1 \ mol \ Na_2CO_3}$

We are converting 57.3 grams to moles, so we multiply by this value.

$57.3 \ g \ Na_2CO_3} *\frac {105.9875386 \ g \ Na_2CO_3}{1 \ mol \ Na_2CO_3}$

Flip the ratio so the units of grams of sodium carbonate cancel.

$57.3 \ g \ Na_2CO_3} *\frac {1 \ mol \ Na_2CO_3}{105.9875386 \ g \ Na_2CO_3}$

$57.3 } *\frac {1 \ mol \ Na_2CO_3}{105.9875386 }$

$\frac {57.3 }{105.9875386 } \ mol \ Na_2CO_3$

$0.5406295944 \ mol \ Na_2CO_3$

The original measurement of moles has 3 significant figures, so our answer must have the same. For the number we found that is the thousandth place. The 6 in the ten-thousandth place to the right tells us to round the 0 up to a 1.

$0.541 \ mol \ Na_2CO_3$

There are approximately <u>0.541 moles of sodium carbonate</u> in 57.3 grams.

6 0

2 years ago