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3 years ago

HELP PLEASE WILL GIVE BRAINLIEST ANSWER

1 answer:

8 0

The volume is the space it takes up, which would be the same. The mass is measured as the weight, and the steel ball would be significantly heavier. Density is mass/volume, and if the steel has a larger mass, it will therefore have a higher density.

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Which answer best describes what is happening in the following reaction?

NISA [10]

A. This is not a redox reaction. It is an example of combustion.

<h3>Combustion reaction of hydrocarbon</h3>

During the combustion of a hydrocarbon, the hydrocarbon reacts with oxygen to create carbon dioxide, water, and heat.

<h3>Example of combustion reaction</h3>

2C8H18 + 25O2 → 16CO2 + 18H2O

Thus, we can conclude that, this is not a redox reaction. It is an example of combustion.

Learn more about combustion here: brainly.com/question/9425444

#SPJ1

8 0

1 year ago

Doctors sometimes use computer models to track the spread of an infectious disease . How might this help them better understand

kotegsom [21]

It could them know how it start when it started wats in the infectious disease and why

7 0

3 years ago

Calculate the standard reaction enthalpy for the reaction NO2(g) → NO(g) + O(g) given +142.7 kJ/mol for the standard enthalpy of

bulgar [2K]

Answer:

The standard reaction enthalpy for the given reaction is 235.15 kJ/mol.

Explanation:

$O_2(g) \rightarrow \frac{2}{3}O_3(g),\Delta H^o_{1}=142.7 kJ/mol$ ..[1]

$O_2(g) \rightarrow 2 O(g),\Delta H^o_{2}=498.4 kJ/mol$ ..[2]

$NO(g) + O_3(g)\rightarrow NO_2(g) + O_2(g) ,\Delta H^o_{3} = -200 kJ/mol$ ..[3]

$NO_2(g)\rightarrow NO(g) + O(g),\Delta H^o_{4}=?$ ..[4]

Using Hess's law:

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

2 × [4] = [2]- (3 ) × [1] - (2) × [3]

$2\times \Delta H^o_{4}=\Delta H^o_{2} -3\times \Delta H^o_{1}-2\times \Delta H^o_{3}$

$2\times \Delta H^o_{4}=498.4 kJ/mol-3\times 142.7 kJ/mol-2\times -200 kJ/mol$

$2\times \Delta H^o_{4}=470.3 kJ/mol$

$\Delta H^o_{4}=\frac{470.3 kJ/mol}{2}=235.15 kJ/mol$

The standard reaction enthalpy for the given reaction is 235.15 kJ/mol.

7 0

3 years ago

A car travels 33.52 miles in 28 minutes. how fast is the car moving

N76 [4]

The answer is 69.69 miles per hour

3 0

2 years ago

1. What is the best method for removing water from a hydrated compound?

Helga [31]

The traditional method is to heat the compound in an oven, on a hot plate or over a Bunsen burner. Waters of hydration are loosely bound in the compound and can be driven off at temperatures below the melting point of the compound. So the answer is heating.

6 0

3 years ago