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3 years ago

What effect does a surfactant have on the surface tension of water

Physics

1 answer:

SpyIntel [72]3 years ago

6 0

Answer:

It weakens its hydrogen bonds causing it to spread out over a surface.

Explanation:

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What is sound energy? List three examples of sound energy that you experienced today.

Helga [31]

1. A broom swishing against the floor
2. a bee buzzing
3. a car engine

hope this helps!

4 0

3 years ago

1. George is traveling to Boston from Springfield. Springfield is 144

denpristay [2]

Answer:

48 kilometers per hour

Explanation:

144/3 = 48 km/h

3 0

2 years ago

Two Earth satellites, A and B, each of mass m = 980 kg , are launched into circular orbits around the Earth's center. Satellite

never [62]

Answer:

Do u have a picture of the graph?

Explanation:

I can solve it with refraction

7 0

3 years ago

Two masses of size m and 4m are connected by a massless thread and are strung over a frictionless pulley of radius R and moment-

tekilochka [14]

Answer:

Total kinetic energy of entire system is 3 mgl

Explanation:

Given two masses: m and 4m.

Since the pulley is frictionless and the thread is massless, the energy here is linked to the two masses.

Total kinetic energy of entire system = decrease in gravitational potential energy of the system.

Therefore, we have :

ΔKE = Δp

ΔKE = 4mgl - mgl

= 3 mgl

Total kinetic energy of entire system is 3 mgl

6 0

3 years ago

An Atwood machine is constructed using a hoop with spokes of negligible mass. The 2.3 kg mass of the pulley is concentrated on i

Sergeu [11.5K]

Answer:

$a = 2.77~{\rm m/s^2}$

Explanation:

Since the pulley has a mass concentrated on its rim, the pulley can be considered as a ring.

The moment of inertia of a ring is

$I = mr^2 = (2.3)(23.5\times 10^{-2})^2 = 0.127$

The mass on the left is heavier, that is the pulley is rotating counterclockwise.

By Newton's Second Law, the net torque is equal to moment of inertia times angular acceleration.

$\tau = I \alpha$

Here, the net torque is the sum of the weight on the left and the weight on the right.

$\tau = m_1gR - m_2gR = (1.65)(9.8)(23.5\times 10^{-2}) - (1)(9.8)(23.5\times 10^{-2}) = 1.497~{\rm Nm}$

Applying Newton's Second Law gives the angular acceleration

$\tau = I\alpha\\1.497 = 0.127\alpha\\\alpha = 11.78~{\rm rad/s^2}$

The relation between angular acceleration and linear acceleration is

$a = \alpha R$

Then, the linear acceleration of the masses is

$a = 11.78 \times 23.5\times 10^{-2} = 2.77~{\rm m/s^2}$

5 0

3 years ago