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Fynjy0 [20]
3 years ago
15

What do scientist need to look at before developing

Physics
1 answer:
pav-90 [236]3 years ago
6 0
Data, without data they can’t develop anything.
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Which two factors does the power of a machine depend on? А. work and distance B.. force and distance C. work and time D. time an
Ivahew [28]

Hello There!

AnimeVines is here!

The answer is...

C. Work and time.

HopeThisHelps!!

AnimeVines

6 0
3 years ago
A 300 g wooden block on a smooth, level surface is firmly attached to a very light horizontal spring with a spring constant of 2
Tom [10]

the solution for the oscillatory movement allows to find the result for the amplitude of the initial displacement is:

  • The range of motion is: A = 4.44 cm

<h3>Oscillatory movement.</h3>

The oscillatory periodic motion of a system occurs when there is a recovered force, in the special case that this force is proportional to the displacement is called simple harmonic motion, which is described by the expression.

            x = A cos (wt + Ф)

            w² = k/m

where x is the displacement, A the amplitude, w the angular velocity, t the time, k the spring constant, m the mass, and Ф a phase constant determined by the initial conditions.

Let's find the angular velocity/

            w= \sqrt{ \frac{200}{0.300} }

            w = 25.8 rad/s

Let's look for the constant Ф, as the system is released from rest its initial velocity is zero, for zero time. The definition of speed is:

             v= \frac{dx}{dt}

             v= - A w sin (wt +Ф)

             

             0 = -A w sin Ф

            Ф= 0

They indicate that at a given instant of the time the velocity is v= 50.0 cm/s and it is in a position x= 4.00 cm, let us write the equations for this time

Position.

               4.00 = A cos 25.8t

Speed.

              50.0 = - At 25.8 sin 25.8t

To solve the system, ;et's square and add.

              Cos² 25.8t = \frac{16}{A^2}

              sin² 25.8t = \frac{3.756}{A^2 }

              1 = \frac{1}{A^2} \ (16 + 3.756)

               A = \sqrt{19.756}

               A= 4.44 cm

In conclusion using the solution for the oscillatory movement we can find the result for the amplitude of the initial displacement is:

The range of motion is: A = 444 cm

Learn more about oscillatory motion here:  brainly.com/question/14311816

4 0
2 years ago
Show that the acceleration of any object down an incline where friction behaves simply (that is, where fk=μkN ) is a=g(sinθ−μkco
11Alexandr11 [23.1K]

Answer:

a=g(sinθ-μkcosθ)

Explanation:

In an inclined plane the forces that interact with the object can be seen in the figure. The normal force, the weight w and the decomposition of the force vector of weight can be observed.

wx=m*g*sinθ

wy=m*g*cosθ

As the objects moves down an incline, acceleration in y axis is 0.

Then, by second Newton's Law:

Fy = m*ay

FN - m*g cos θ = 0,

FN=m*g cos θ

In x axis the forces that interacs are the x component of weight and friction force:

Fx = m*ax

mg sen u-FN*μk=m*a

Being friction force, Fr=FN*μk, we replace with its value in below formula:

m*g *sinθ-(m*g*cosθ*μk)=m*a

Then, isolating a:

a=(m*g sinθ-(m*g*cosθ*μk))/m

Solving, we have next equation:

a=g sinθ-(g*cosθ*μk)

Applying distributive property we have:

a=g*(sinθ-μk*cosθ)

5 0
3 years ago
Using a simple machine, a student is able to lift a 500N weight by applying only 100N.
pishuonlain [190]
Hey there!

a \ student  \ is \ able \ to \ lift \ a \ 500(n) \\ weight \ by \ applying \ only  \ 100(n) \\ \\ so, \ this \ info \ here, \ we \ simply \ divide \ by \\ how \ much \ this \ kid \ lifted, \ by \ the \ weight \ he/she \\ \ is \ applying. \\ \\   \left[\begin{array}{ccc}\boxed{\boxed{500(n)/100(n)}}\end{array}\right] \\ \\ and \ from \ this,\ your \ answer \ would \ \\ conclude \ to \ be \ (5) \\ \\ \boxed{5} \ would \ be \ your \ answer!

Hope this helps you!
7 0
3 years ago
What type of image is formed by a mirror if m= -6.1?
mrs_skeptik [129]
I Think The answer is a I hope it helps My friend Message Me if I’m wrong and I’ll change My answer and fix it for you
5 0
2 years ago
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