<em>T</em><em>he great size or extent of something.
</em>
<em></em>
Answer:
534 j
Explanation:
100 lbs = 45.359 kg
work = F * d
= 45.359 * 9.81 * 1.2 = ~ 534 j
Answer:
The average speed during the trip is 6.16 
Explanation:
Speed is a physical quantity that expresses the variation in position of an object and as a function of time. In other words, speed expresses the relationship between the space traveled by an object, the time used for it and its direction.
The speed can be calculated by the expression:
Aaron rode his bike home for 1.6 hours at 6.5 km/h and another 15 minutes at 4 km/h. So, the distance in each of the stages can be calculated as, taking into account that 60 minutes= 1 hour:
- distance1=speed*time= 6.5
*1.6 hours= 10.4 km
- distance2= speed*time= 4 *15 minutes= 4 *0.25 hours= 1 km
So:
- total distance= 10.4 km + 1 km= 11.4 km
- total time= 1.6 hours + 0.25 hours= 1.85 hours
Then:
<u><em>The average speed during the trip is 6.16 </em></u><u><em></em></u>
The answer is; pressure
The sound is a longitudinal wave meaning the particles vibrate parallel to the direction of the wave. Sound waves, therefore, produce compression (akin to the crest in a transverse wave) and rarefaction regions (akin to a trough in a transverse wave) as its energy is propagated in the medium.
Answer:
165.8 V/m
Explanation:
The capacitance of a long concentric cylindrical shell of length, L and inner radius, a and outer radius, b is C = 2πε₀L/㏑(b/a)
Since the charge on the cylindrical shells, Q = CV where V = the potential difference across the capacitor(which is the potential difference between the concentric cylindrical shells)
V = Q/C
V = Q ÷ 2πε₀L/㏑(b/a)
V = Q㏑(b/a)/2πε₀L
So, the potential difference per unit length V' is
V' = V/L = Q㏑(b/a)/2πε₀
Given that a = inner radius = 1.5 cm, b = outer radius = 5.6 cm and Q = 7.0 nC = 7.0 × 10⁻⁹ C and ε₀ = 8.854 × 10⁻¹² F/m substituting the values of the variables into the equation, we have
V' = Q㏑(b/a)/2πε₀
V' = 7.0 × 10⁻⁹ C㏑(5.6 cm/1.5 cm)/(2π × 8.854 × 10⁻¹² F/m)
V' = 7.0 × 10⁻⁹ C㏑(3.733)/(55.631 × 10⁻¹² F/m)
V' = 7.0 × 10⁻⁹ C × 1.3173/(55.631 × 10⁻¹² F/m)
V' = 9.2211 × 10⁻⁹ C/(55.631 × 10⁻¹² F/m)
V' = 0.16575 × 10³ V/m
V' = 165.75 V/m
V' ≅ 165.8 V/m
