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maxonik [38]
3 years ago
5

Which model is most similar to that of Aristarchus?

Physics
2 answers:
alina1380 [7]3 years ago
6 0

Answer:

A. First one with Sun at the center.

Explanation:

Aristarchus was a Greek scientist who proposed the theory that its not Earth which is fixed, its the Sun that has a fixed position and is placed at center where are all other planets are located at some distance from it and revolve around it.

This theory is referred as "Heliocentric".  His theories were even attributed by Nicolaus Copernicus and was even know as Copernicus heliocentrism.

Ray Of Light [21]3 years ago
4 0

Answer:The first one , option a

Explanation:

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Trong máy phát điện xoay chiều ba pha khi tổng điện áp tức thời của cuộn 1,2 là e1+e2=120V thì điện áp tức thời của cuộn 3 là
NARA [144]

Answer:

I just noticd i dont speak this launguage

Explanation:

8 0
3 years ago
An FM radio station broadcasts electromagnetic radiation at a frequency of 93.5 MHz. The wavelength of this radiation is _______
Alborosie

Answer:

3.21

Explanation:

The relation between frequency and wavelength is shown below as:

c=frequency\times Wavelength


c is the speed of light having value 3\times 10^8\ m/s

Given, Frequency = 93.5 MHz = 93.5\times 10^{6}\ Hz

Thus, Wavelength is:

Wavelength=\frac{c}{Frequency}

Wavelength=\frac{3\times 10^8}{93.5\times 10^{6}}\ m

Wavelength=3.21 \ m

<u>Answer - A.</u>

7 0
3 years ago
What happens to the kinetic energy of a body when: a) the mass of the body is doubled at constant velocity? b) the velocity of t
blagie [28]
Using the formula KE=1/2mv^2

a: The kinetic energy doubles.
b: The kinetic energy quadruples.
c: The kinetic energy is cut in half.
Hopefully it’s clear how the formula can show you this.
3 0
3 years ago
A speed skater moving across frictionless ice at 9.2 m/s hits a 5.0 m wide patch of rough ice. She slows steadily, then continue
enot [183]

Answer:

a = -5.10 m/s^2

her acceleration on the rough ice is -5.10 m/s^2

Explanation:

The distance travelled on the rough ice is equal to the width of the rough ice.

distance d = 5.0 m

Initial speed u = 9.2 m/s

Final speed v = 5.8 m/s

The time taken to move through the rough ice can be calculated using the equation of motion;

d = 0.5(u+v)t

time t = 2d/(u+v)

Substituting the given values;

t = 2(5)/(9.2+5.8)

t = 2/3 = 0.66667 second

The acceleration is the change in velocity per unit time;

acceleration a = ∆v/t

a = (v-u)/t

Substituting the values;

a = (5.8-9.2)/0.66667

a = -5.099974500127

a = -5.10 m/s^2

her acceleration on the rough ice is -5.10 m/s^2

7 0
3 years ago
What is pitch related to?
Jlenok [28]
Pitch is related to frequency
7 0
3 years ago
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