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padilas [110]
3 years ago
5

It is not advisable to wear clothes made of synthetic fiber while working near fire because?

Chemistry
1 answer:
Svetradugi [14.3K]3 years ago
8 0

Answer:

They catch fire very easily.

Explanation:

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How many moles of MgO can be made from 5 moles of Mg?<br> 2Mg + O2 -&gt; 2MgO
kkurt [141]

Answer:

Explanation:

The expected product is MgO, so the 1-to-1 mole ratio Mg to O in the product is all that is required.

3 0
3 years ago
How many moles of Fe2+ are there in a 2.0g sample that is 80% by mass of FeCl2?
KIM [24]

Answer:

A walkthrough for a sample titration calculation for all levels of chemistry. ... Now that gives us the moles of Fe2+, but it's asking for how many grams there are. ... The molar mass of iron is about 55.8, so we'll just put that.

অনুপস্থিত: 80%

Explanation:

5 0
2 years ago
An animal can ____.
e-lub [12.9K]
The answer is B!! hope this helps(: an example is a zebra or a lion
4 0
2 years ago
(part 1 of 3) Copper reacts with silver nitrate through a single replacement. If 1.29 g of silver are produced from the reaction
ale4655 [162]

Answer:

See explanation.

Explanation:

Hello there!

In this case, according to the described chemical reaction, we first write the corresponding equation to obtain:

Cu+2AgNO_3\rightarrow 2Ag+Cu(NO_3)_2

Thus, we proceed as follows:

Part 1 of 3: here, since the molar mass of silver and copper (II) nitrate are 107.87 and 187.55 g/mol respectively, and the mole ratio of the former to the latter is 2:1, we can set up the following stoichiometric expression:

m_{Cu(NO_3)_2}=1.29gAg*\frac{1molAg}{107.87gAg}*\frac{1molCu(NO_3)_2}{2molAg}*\frac{187.55gCu(NO_3)_2}{1molCu(NO_3)_2}   \\\\m_{Cu(NO_3)_2}=1.12gCu(NO_3)_2

Part 2 of 3: here, the molar mass of copper is 63.55 g/mol and the mole ratio of silver to copper is 2:1, the mass of the former that was used to start the reaction was:

m_{Cu}=1.29gAg*\frac{1molAg}{107.87gAg}*\frac{1molCu}{2molAg}*\frac{63.55gCu)_2}{1molCu}   \\\\m_{Cu}=0.380gCu

Part 3 of 3: here, the molar mass of silver nitrate is 169.87 g/mol and their mole ratio 2:2, thus, the mass of initial silver nitrate is:

m_{AgNO_3}=1.29gAg*\frac{1molAg}{107.87gAg}*\frac{2molAgNO_3}{2molAg}*\frac{169.87gAgNO_3}{1molAgNO_3}   \\\\m_{AgNO_3}=2.03gAgNO_3

Best regards!

5 0
3 years ago
Help please!! I'll name you brainliest!!
balu736 [363]

Answer:

MgO

Explanation:

4 0
3 years ago
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