Answer:3480s⁻¹
Explanation:We can solve the following problem using the Arrhenius equation.
Arrhenius equation is given by:
![K=Aexp[-Ea/RT]](https://tex.z-dn.net/?f=K%3DAexp%5B-Ea%2FRT%5D)
A=Pre-exponential factor or frequency factor
Ea=Activation energy
R=Ideal gas constant
T=Temperature
K=Rate constant
From the Arrhenius equation we can see that the rate constant K is related with the activation energy and frequency factor.
In the question we are given with the following data:
Ea=42KJ/mol=42x 1000 J/mol
A=8.0×10¹ per second
T=298K
R=8.314J/K mol
when we substitute these given values in Arrhenius equation
![K=A{exp[-Ea \div RT]}\\K=8\ \times10^{10} s^{-1}{exp[-42000\div 8.314\times298]}\\K=8\ \times10^{10} s^{-1}{exp[-16.95]}\\K=4.35\times10^{^{-8}}\times8.0\times10^{^{10}}s^{-1}\\K=34.8\times10^{2}s^{-1}\\](https://tex.z-dn.net/?f=K%3DA%7Bexp%5B-Ea%20%5Cdiv%20RT%5D%7D%5C%5CK%3D8%5C%20%5Ctimes10%5E%7B10%7D%20s%5E%7B-1%7D%7Bexp%5B-42000%5Cdiv%208.314%5Ctimes298%5D%7D%5C%5CK%3D8%5C%20%5Ctimes10%5E%7B10%7D%20s%5E%7B-1%7D%7Bexp%5B-16.95%5D%7D%5C%5CK%3D4.35%5Ctimes10%5E%7B%5E%7B-8%7D%7D%5Ctimes8.0%5Ctimes10%5E%7B%5E%7B10%7D%7Ds%5E%7B-1%7D%5C%5CK%3D34.8%5Ctimes10%5E%7B2%7Ds%5E%7B-1%7D%5C%5C)
K=3480s⁻¹
The value of rate constant obtained is 3480s⁻¹.
Answer:
c) i) Mg²⁺ ii) O²⁻
Explanation:
I don't know the answer to Q7. because you don't show the diagram
Answer:
An acid is a substance that releases H⁺ in aqueous solution.
Explanation:
There are different acid-base theories, such as Arrhenius, Bronsted-Lowry, Lewis, etc.
According to the Arrhenius theory, an acid is a substance that releases H⁺ in aqueous solution.
HCl(aq) → H⁺(aq) + Cl⁻(aq)
On the other hand, according to the Arrhenius theory, a base is a substance that releases OH⁻ in aqueous solution.
NaOH(aq) → Na⁺(aq) + OH⁻(aq)