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True [87]
2 years ago
10

PLEASE HELP

Chemistry
2 answers:
blondinia [14]2 years ago
7 0

Answer:

c elevation

Explanation:

svet-max [94.6K]2 years ago
6 0

C is the answer for your question

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What are two examples of homogeneous<br>​
Andrei [34K]

Answer:

two examples are blood and soapy water.

Explanation:

7 0
2 years ago
: An unknown metal crystallizes in the cubic crystal structure. The metal has a radius 140pm, atomic mass of 135 g/mol, and dens
ki77a [65]

The cubic unit cell  this metal crystallize as is BCC structure .

<h3> What is unit cell ?</h3>

The structure of a crystalline solid, whether a metal or not, is best described by considering its simplest repeating unit, which is referred to as its unit cell.

The unit cell consists of lattice points that represent the locations of atoms or ions.

The entire structure then consists of this unit cell repeating in three dimensions

\rm \rho =\dfrac{nM}{N_{0} a^{3}} \\\\\\\\\rm n =\dfrac{\rho N_{0} a^{3}}{M} \\\\\\\\Assuming\; it \; to \; be \; a\; BCC\; structure \\\\\\ r = \dfrac{\sqrt{3} \times a}{4} \\\\\\Therefore\; a = 3.23 \times 10^{-8}\\\\\\\\\rm n =\dfrac{13.3 \times 6.022 \times 10^{23}\times 3.23^{3}\times (10^{-8})^{3}}{135} \\\\

n= 2

Hence our assumption was correct

It is a BCC structure .

Therefore the cubic unit cell  this metal crystallize as is BCC structure .

To know more about unit cell

brainly.com/question/13110055

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5 0
2 years ago
explain the relationship between the rate of effusion of a gas and its molar mass. methane gas (ch4) effuses 3.4 times faster th
Musya8 [376]

The molar mass of the unknown gas is 184.96 g/mol

<h3>Graham's law of diffusion </h3>

This states that the rate of diffusion of a gas is inversely proportional to the square root of the molar mass i.e

R ∝ 1/ √M

R₁/R₂ = √(M₂/M₁)

<h3>How to determine the molar mass of the unknown gas </h3>

The following data were obtained from the question:

  • Rate of unknown gas (R₁) = R
  • Rate of CH₄ (R₂) = 3.4R
  • Molar mass of CH₄ (M₂) = 16 g/mol
  • Molar mass of unknown gas (M₁) =?

The molar mass of the unknown gas can be obtained as follow:

R₁/R₂ = √(M₂/M₁)

R / 3.4R = √(16 / M₁)

1 / 3.4 = √(16 / M₁)

Square both side

(1 / 3.4)² = 16 / M₁

Cross multiply

(1 / 3.4)² × M₁ = 16

Divide both side by (1 / 3.4)²

M₁ = 16 / (1 / 3.4)²

M₁ = 184.96 g/mol

Learn more about Graham's law of diffusion:

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3 0
2 years ago
An atom of element A has 108 protons. What would the elements atomic number be?
marusya05 [52]

108 is the atomic number

3 0
3 years ago
A sample of gas originally at 25 C and 1.00 atm pressure in a 2.5 L container is allowed to expand until the pressure is 0.85 at
aivan3 [116]

Answer:

Final volumeof the gas = 2.84 L

Explanation:

The formular to be used here is the general gas equation. the formular is being used because it gives the relationship between the three gas parameters (volume, temperature and pressure) mentioned.

The general gas equation is given as;

\frac{P1V1}{T1} = \frac{P2V2}{T2}

where;

P1 = initial pressure

V1 = initial volume

T1 = initial temperature

P2 = Final pressure

V2 = Final volume

T2 = Final temperature

From the question,

P1 = 1.00 atm

P2 = 0.85atm

T1 = 25C + 273 = 298K (Converting to kelvin)

T2 = 15C + 273 = 288K (Converting to kelvin)

V1 = 2.5L

V2 = ?

from the equation, making V2 subject of formula we have;

V2 = \frac{T2P1V1}{T1P2}

V2 = (1*2.5*288)/(298*0.85) = 2.84 L.

5 0
3 years ago
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