<u>Given information:</u>
Mass of NaCl (m) = 87.75 g
Volume of solution (V) = 500 ml = 0.5 L
Molar mass of NaCl (M) = 58.44 g/mol
<u>To determine:</u>
The molarity of NaCl solution
<u>Explanation:</u>
Molarity is defined as the number of moles of solute(n) dissolved per liter of solution (V)
i.e. M = moles of solute/liters of solution = n/V
Moles of solute (n) = mass of solute (m)/molar mass (M)
moles of NaCl = 87.75 g/58.55 g.mol-1 = 1.499 moles
Therefore,
Molarity of NaCl = 1.499 moles/0.5 L = 2.998 moles/lit ≅ 3 M
<u>Ans: (D)</u>
Answer:
The gas occupy 2406.4 mL at 80 K.
Explanation:
Given data:
Initial volume of gas = 752 mL
Initial temperature = 25 K
Final temperature = 80 K
Final volume = ?
Solution:
The given problem is solved by using charle's law.
V₁/T₁ = V₂/T₂
V₂ = V₁. T₂ /T₁
V₂ = 752 mL × 80 k / 25 K
V₂ = 60160 mL. k/25 K
V₂ = 2406.4 mL
Use the ideal gas formula-----> PV= nRT
P= 2.50 atm
V= 250 mL= 0.250 L
n= 0.100 moles
R= 0.0821 atmxL/molesxK
T= ?
T= PV/nR
T= (2.50 atm x 0.250 L) / (0.100 moles x 0.0821)= 76.1 K
Answer:

Explanation:
Here, we want to calculate the number of moles of methane in the container
From the ideal gas law:

where:
P is the pressure inside the container which is 3 atm
V is the volume of the container which is 2 L
R is the molar gas constant which is 0.0821 Latm/mol.k
T is the temperature in Kelvin (we convert the temperature in Celsius by adding 273 : 273 + 77 = 350 K)
n is the number of moles that we want to calculate
Substituting the values, we have it that: