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amid [387]
3 years ago
7

Item 10

Physics
1 answer:
melisa1 [442]3 years ago
5 0

Answer:

D. mass to see how it affected stretch length of a rubber band

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When a substance goes directly from a gaseous state to a solid state as dry ice does
Naddik [55]

Answer:  Sublimation I think.

Explanation:

6 0
3 years ago
Read 2 more answers
John and mary are skating at an ice rink. john skates at a constant speed of 6.7 m/s, with respect to the ice surface, directly
iragen [17]
60.3° from due south and 5.89 m/s    For this problem, first calculate a translation that will put John's destination directly on the origin and apply that translation to Mary's destination. Then the vector from the origin to Mary's new destination will be the relative vector of Mary as compared to John. So John is traveling due south at 6.7 m/s. After 1 second, he will be at coordinates (0,-6.7). The translation will be (0,6.7)  Mary is traveling 28° West of due south. So her location after 1 second will be  (-sin(28)*10.9, -cos(28)*10.9) = (-5.117240034, -9.624128762)  After translating that coordinate up by 6.7, you get  (-5.117240034, -2.924128762)  The tangent of the angle will be 2.924128762/5.117240034 = 0.57142693  The arc tangent is atan(0.57142693) = 29.74481039° Subtract that value from 90 since you want the complement of the angle which is now 60.25518961°    So Mary is traveling 60.3° relative to due south as seen from John's point of view.  The magnitude of her relative speed is  sqrt(-5.117240034^2 + -2.924128762^2) = 5.893783 m/s    Rounding the results to 3 significant digits results in 60.3° and 5.89 m/s
8 0
3 years ago
There is a 50 g sample of Ra-229. It has a half-life of 4 minutes.
Sloan [31]

Via half-life equation we have:


A_{final}=A_{initial}(\frac{1}{2})^{\frac{t}{h} }


Where the initial amount is 50 grams, half-life is 4 minutes, and time elapsed is 12 minutes.  By plugging those values in we get:

A_{final}=50(\frac{1}{2})^\frac{12}{4}=50(\frac{1}{2})^{3}=50(\frac{1}{8})=6.25g


There is 6.25 grams left of Ra-229 after 12 minutes.

4 0
4 years ago
A rock with a mass of 6.1 kg falls 1.5 m. What potential energy does it have before the fall?
denpristay [2]

89.67J

Explanation:

Given parameters:

Mass of rock = 6.1kg

Height of fall = 1.5m

Unknown:

Potential energy = ?

Solution:

The potential energy is the energy at rest or due to the position of a body.

Potential energy is mathematically expressed as;

  Potential energy = mgh

m is the mass of the rock

g is the acceleration due to gravity of the rock

h is the height of the rock

   Potential energy = 6.1 x 9.8 x 1.5 = 89.67J

learn more:

Potential energy brainly.com/question/10770261

#learnwithBrainly

6 0
3 years ago
A cheetah is running 10m/s when it sees its prey & accelerates to 35m/s. The cheetah travels 115m before it stops. What is t
Nesterboy [21]

Answer:

the the the the eeeeeeeeeeeeeeeeeeeeee

Explanation:

4 0
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