Answer:
The minimum wall thickness required for the spherical tank is 0.0189 m
Explanation:
Given data:
d = inside diameter = 8.1 m
P = internal pressure = 1.26 MPa
σ = 270 MPa
factor of safety = 2
Question: Determine the minimum wall thickness required for the spherical tank, tmin = ?
The allow factor of safety:
The minimun wall thickness:
Answer:
3.7 m/s^2
Explanation:
The period of a simple pendulum is given by:
where L is the length of the pendulum and g is the free-fall acceleration on the planet.
Calling L the length of the pendulum, we know that:
is the period of the pendulum on Earth, and
is the free-fall acceleration on Earth
is the period of the pendulum on Mars, and
is the free-fall acceleration on Mars
Dividing the two expressions we get
And re-arranging it we can find the value of the free-fall acceleration on Mars:
This question is incomplete, the complete question is on the image uploaded along this answer.
Answer:
the potential at point B is 5 V, Option d) is the correct answer
Explanation:
Given that;
from the image;
R = 3 + 4 + 5 = 12 Ω
so I = 12/12 = 1 A
Q = 0 + 12 = 12 V
now
VA - VQ = - I × 3 = -3 V
VA = VQ - 3 = 12 - 3 = 9 V
VB - VA = - I × 4Ω = - 4 V
⇒VB = VA - 4 = 9 V - 4 V = 5 V
Therefore the potential at point B is 5 V
Option d) is the correct answer
