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Iteru [2.4K]
3 years ago
10

Please help me please​

Physics
1 answer:
uranmaximum [27]3 years ago
3 0

Answer:

what do you need help with?

Explanation:

I don't see any image or question

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9. How much work is done when a 15kg box is lifted to a height of 2 meters?
torisob [31]

Answer: W = 294 J

Explanation: Solution:

Work is expressed as the product of force and the distance of the object.

W = Fd        where F = mg

W= Fd

   = mg d

   = 15 kg ( 9.8 m/s²) ( 2m )

   = 294 J

5 0
3 years ago
Determine the number of atoms per unit cell in a (a) face-centered cubic, (b) body- centered cubic, and (c) diamond lattice.
fredd [130]

Answer:

a) 4

b) 2

c) 8

Explanation:

In a cubic lattice, each atom of the vertex is shared among other 8 unit cells, so the atoms on the vertex contribute to 1/8 to a given unit cell.

a) Ina face-centered cubic we have 8 atoms on the vertex and one in each face, which is shared with another unit cell, so it contribute to 1/2

Therefore, the total atoms are:

8*(1/8) + 6*(1/2) = 4

b) In the body centered cubic structure, the centered atom is not shared with another cell, therefore it contribute to 1 to the given cell:

The number of atoms per unit cel is:

8*(1/8) + 1 = 2

c) The diamond lattice is similar to the face-centered cubic lattice but it contains two identical atoms per lattice point.

Therefore it must contain twice atoms than the face-centered cubic lattice:

that is, it has 8 atoms per unit cell

3 0
4 years ago
What term best describes the function of
Alja [10]
Lol idkddddddddddddddddd
4 0
4 years ago
Read 2 more answers
A ball is thrown with an initial velocity of 20 m/s at an angle of 60° above the horizontal. If we can neglect air resistance, (
Neporo4naja [7]

Answer:

10 m/s

1.87914 s

18.7914 m

Explanation:

v = Initial velocity = 20 m/s

\theta = Angle = 60°

Horizontal component is given by

v_x=20cos60\\\Rightarrow v_x=10\ m/s

The horizontal component is 10 m/s

y direction final displacement is zero

s=vsin \theta t+\frac{1}{2}at^2\\\Rightarrow 0=20sin60+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow t=\sqrt{\frac{2\times 20sin 60}{9.81}}\\\Rightarrow t=1.87914\ s

The time the ball is in the air is 1.87914 s

Range is given is by

R=vcos\theta t\\\Rightarrow R=10\times 1.87914\\\Rightarrow R=18.7914\ m

The range is 18.7914 m

6 0
4 years ago
What is the force of friction acting on this box? N What is the net force acting on this box? N to the
Zanzabum

Answer: -3, 12, right

Explanation:

n/a just did the test

5 0
3 years ago
Read 2 more answers
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