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harina [27]
2 years ago
12

A 10-newton force is applied to a 2-kg block. The block slides across the floor at a constant speed of 5 m/s. What is a valid co

nclusion from this situation?
A) The force of friction was 10-newtons.
B) The 10-newton force was an unbalanced force.
C) There was no friction experienced by the block.
D) There is a net a force of 10-newtons on the block.
Physics
2 answers:
katrin2010 [14]2 years ago
7 0

A)  The force of friction was 10-newtons.

The force of friction was 10-newtons. If the block is moving at constant speed, all the forces on the block must be balanced.

Svetlanka [38]2 years ago
5 0

Answer:

The frictional force will also act on the box. So, we can say that the 10 N force is an unbalanced force.

Explanation:

It is given that, a 10-Newton force is applied to a 2-kg block. The block slides across the floor at a constant speed of 5 m/s.

The block is sliding with a constant speed. This shows the acceleration of the block is zero.

When an object slides that means the force acting on it is unbalanced i.e. the object will move in a particular direction.

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A car is traveling at 50 mi/h when the brakes are fully applied, producing a constant deceleration of 38 ft/s2. what is the dist
e-lub [12.9K]

Convert 38 ft/s^2 to mi/h^2. Then we se the conversion factor > 1 mile = 5280 feet and 1 hour = 3600 seconds.

So now we show it > 38  \frac{ft}{s^2}  x  \frac{1mi}{5280ft} x  \frac{(3600s)^2}{(1h)^2} = 93272.27  \frac{mi}{h^2}

Then we have to use the formula of constant acceleration to determine the distance traveled by the car before it ended up stopping.

Which the formula for constant acceleration would be > v_2^2=v_1^2 + 2as

The initial velocity is 50mi/h (v_1=50)

When it stops the final velocity is (v_2=0)

Since the given is deceleration it means the number we had gotten earlier would be a negative so a = -93272.27

Then we substitute the values in....

0^2 = 50^2 + 2(-93272.27)s

0 = 2500 - 186544.54s

Isolate S next.

185644.54s= 2500

s =  2500/(185644.54)

s=0.0134


So we can say the car stopped at 0.0134 miles before it came to a stop but to express the distance traveled in feet we need to use the conversion factor of 1 mile = 5280 feet in otherwards > 0.0134 mi *  \frac{5280ft}{1mi}  = 70.8 ft
So this means that the car traveled in feet 70.8 ft before it came to a stop.

4 0
2 years ago
Ph11_UnitPacket2019
frozen [14]

Let's see

Use snells law

\\ \rm\Rrightarrow \dfrac{n_1}{n_2}=\dfrac{sini}{sinr}

\\ \rm\Rrightarrow \mu=\dfrac{sin30}{sin19.9}

\\ \rm\Rrightarrow \mu=0.5/0.34

\\ \rm\Rrightarrow \mu=1.47

It may be glass

3 0
2 years ago
Transformer is used in rectifier step up and step down voltage?<br>​
tensa zangetsu [6.8K]

Answer:

While the use of the type of transformer in a rectifier depends on the voltage requirement or to meet desired operating conditions, a step-down transformer is used mainly to reduce the voltage. It is used to bring the high AC voltage level to a reasonable value or the desired output voltage.

Explanation:

Hope it helps

Correct me if Im wrong

3 0
2 years ago
a baby carriage is sitting on the top of a hill that is 21 m high. the carriage with a baby 75kg. the carriage has what energy?
lara31 [8.8K]

Answer:

It has potential energy

PE = 15450.75 J

Explanation:

we know its potential energy because the carriage is not moving, although it can

PE = mgh

in this case, m is 75, h is 21, and g is always 9.81

plug these in: PE = (75) (21) (9.81)

your answer: PE = 15450.75 J

4 0
2 years ago
An electric iron is connected to the mains power supply of 220 V. When the electric iron is
Ilya [14]

Answer:

Given: V = 220V, Pmin = 360W, Pmax = 840W

For minimum heating case:

We know that

Pmin = VI

360 = 220 X I

I = 1.63 amp

R = V/I

R = 220/1.63

R = 134.96ohms

For maximum heating case:

We know that

Pmax = VI

840 = 220 X I

I = 3.81 amp

R = V/I

R = 220/3.81

R = 57.74 ohms

7 0
2 years ago
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