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tekilochka [14]
3 years ago
5

73 m is equal to ____ dm. (Only input whole number answer.)

Chemistry
2 answers:
GenaCL600 [577]3 years ago
6 0

<u>Answer:</u> 73 m is equal to 730 dm

<u>Explanation:</u>

Meter and decimeter are the units which are used to express the length of an object.

These two units are interchangeable.

To convert meter into decimeter, we use the conversion:

1 meter = 10 decimeter

We are given the value of length is 73 m

Converting this into decimeter, we get:

\Rightarrow (73m)\times (\frac{10dm}{1m})\\\\\Rightarrow 730dm

Hence, 73 m is equal to 730 dm

erma4kov [3.2K]3 years ago
5 0

73 m is equal to 730 dm.

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Answer:

It will most likely be the first answer

Explanation:

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Calculate the mass of vanadium(V) oxide (V2O5) that contains a million (1.0 *10^6) vanadium atoms. Be sure your answer has a uni
sweet [91]

Answer : The mass of vanadium(V) oxide will be 1.51\times 10^{-16}g

Explanation : Given,

Number of atoms of V_2O_5 = 1.0\times 10^{6}

Molar mass of V_2O_5 = 181.88 g/mole

In V_2O_5, there are 2 atoms of vanadium and 5 atoms of oxygen.

First we have to determine the moles of V_2O_5.

As, 2\times 6.022\times 10^{23} number of vanadium atom present in 1 moles of V_2O_5

So, 1.0\times 10^{6} number of vanadium atom present in \frac{1.0\times 10^{6}}{2\times 6.022\times 10^{23}}=8.3\times 10^{-19} moles of V_2O_5

Now we have to determine the mass of V_2O_5.

\text{Mass of }V_2O_5=\text{Moles of }V_2O_5\times \text{Molar mass of }V_2O_5

\text{Mass of }V_2O_5=(8.3\times 10^{-19}mole)\times (181.88g/mole)=1.51\times 10^{-16}g

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4 years ago
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Need Help ASAP- Chemistry
jarptica [38.1K]

Answer:

Q1: 1.67 L.

Q2: Saturated solution.

Explanation:

<u><em>Q1:</em></u>

  • We have the role that the no. of millimoles before dilution is equal to the no. of millimoles after dilution.

<em>(MV) before dilution = (MV) after dilution</em>

M before dilution = 10.0 M, V before dilution = 0.5 L.

M after dilution = 3.0 M, V after dilution = ??? L.

<em>∴ V after dilution = (MV) before dilution / M after dilution</em> = (10.0 M)(0.5 L) / (3.0 M) =<em> 1.67 L.</em>

<em></em>

<em></em>

<u><em>Q2:</em></u>

From the given curve, it is clear that the solubility of sodium nitrate at 35.0°C is 100 g per 100 g of water.

<em>So, the mentioned solution is a saturated solution at this T.</em>

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3 years ago
water and ammonia are polar. The hydrogen atoms in each have a slight positive charge. What does that tell you about the oxygen
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Answer:

More electronegative

Explanation:

The oxygen and nitrogen in ammonia shows that they are more electronegative than the hydrogen  atoms.

  • Electronegativity shows the affinity of an atom for valence electrons.
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The oxygen atom in water and the nitrogen atom in ammonia are more electronegative.

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Answer:

The solution's new volume is 1.68 L

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Dilution is the procedure to prepare a less concentrated solution from a more concentrated one, and simply consists of adding more solvent. So, in a dilution the amount of solute does not vary, but the volume of the solvent varies.

In summary, a dilution is a lower concentration solution than the original.

The way to do the calculations in a dilution is through the expression:

Ci*Vi=Cf*Vf

where C and V are concentration and volume, respectively; and the i and f subscripts indicate initial and final respectively.

In this case, being:

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