Answer:
4.4 mol.
Explanation:
Hello!
In this case, since the formula for calculating the molarity is:
Whereas n stands for moles and V for the volume in liters; we can solve for n as shown below when we are given the volume and the molarity:
Thus, we plug in the given data to obtain:
Best regards!
Answer:
For every 4 moles of NO created, 6 moles of H2O are created so the ratio is 4:6
Explanation:
You just need to balance the equation.
NH3 + O2 -> NO + H2O
1. I started with hydrogen; there's 3 on the left and 2 on the right. Multiply them together to find a number they both go into (3×2=6, but in this case 6 hydrogen on each side does not work so I doubled it so there is 12 hydrogen on each side).
This will bring you to this:
4NH3 + O2 -> NO + 6H2O
2. Now get equal amounts of nitrogen on each side. There's 4 nitrogen on the left side, and 1 on the right. Multiply the right by 4. Then you will have this:
4NH3 + O2 -> 4NO + 6H2O
3. Last thing you need to do is have the same amount of oxygen on both sides. On the left you have 2 and on the right you have 10. Get the left to 10 by multiplying it by 5.
Balanced: 4NH3 + 5O2 -> 4NO + 6H2O
In word form, for every reaction between 4 moles of ammonia and 5 moles of oxygen, 4 moles of nitric oxide and 6 moles of water will be created.
I hope this helps!
Is bubble chamber one of your choices? Bubble chamber sounds like a good fit for the question.
CO2 ; H20- They are the only ones that, on both sides, combined with another element and bonding of atoms
