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____ [38]
4 years ago
15

When a pure substance melts does its particles get larger

Chemistry
1 answer:
ziro4ka [17]4 years ago
4 0
I think so ( for solids ) because you know when you melt chocolate it turns into a liquid and liquids allways move around together and it can't get smaller either so, I think you are right.
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Doing a crossword puzzle on ionic bonds. "Metals are usually _____ of electrons."<br> 6 letters
zhannawk [14.2K]
Metals are usually givers of electrons.
5 0
3 years ago
How much oxygen be required to produce 3.9 mol of water
timofeeve [1]

Answer:

1.95mol

Explanation:

First let us generate the equation for the reaction:

2H2 + O2 —> 2H2O

From the equation,

1mole of O2 reacted to produce 2moles of H2O.

Therefore, Xmol of O2 will react to produce 3.9 mol of H2O i.e

Xmol of O2 = 3.9/2 = 1.95mol

6 0
3 years ago
At sea level, a pressure gauge on a closed rigid tank reads 20.0 psi. The tank is moved to a location where the atmospheric pres
Soloha48 [4]

Answer:

It won't change.

-26F=3.33C

Explanation:

The pressure won't change since the system is closed and its volume is the exact same, the only way to change the tanks pressure is to open or pump more gas into or changing the temperature.

- To convert Fahrenheit to Celsius, you need to subtract 32 and divide by 1.8, in the next equation will substitute 26 F.

C=(F-32)\1.8

C=(26-32)\1.8

C=-3.33

I hope you find this information useful and interesting, good luck!

3 0
4 years ago
Calculate the wavelength of the photon that would be absorbed or emitted. Round your answer to 3 significant digits.
Flauer [41]

This is an incomplete question, the image for the given question is attached below.

Answer : The wavelength of photon would be absorbed, 3.06\times 10^{-7}m

Explanation :

From the given diagram of energy we conclude that,

Energy at ground state, A = 400 zJ

Energy of 2nd excited state, C = 1050 zJ

Now we have to calculate the energy of the photon.

E=E_c-E_A

E=(1050-400)zJ= 650zJ=650\times 10^{-21}J

Now we have to calculate the wavelength of the photon.

Formula used :

E=h\times \nu

As, \nu=\frac{c}{\lambda}

So, E=h\times \frac{c}{\lambda}

where,

E = energy of photon = 650\times 10^{-21}J

\nu = frequency of photon

h = Planck's constant = 6.626\times 10^{-34}Js

\lambda = wavelength of photon  = ?

c = speed of light = 3\times 10^8m/s

Now put all the given values in the above formula, we get:

650\times 10^{-21}J=(6.626\times 10^{-34}Js)\times \frac{(3\times 10^{8}m/s)}{\lambda}

\lambda=3.06\times 10^{-7}m

Therefore, the wavelength of photon would be absorbed, 3.06\times 10^{-7}m

5 0
3 years ago
How many alkenes have the formula c5h10?<br> a. 4<br> b. 5<br> c. 6<br> d. 7?
sashaice [31]
C, 6. hope this message helps! <3
7 0
4 years ago
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