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timama [110]
2 years ago
13

13.What volume of hydrogen gas is produced when 92.4 g of sodium reacts completely according to the following reaction at 25 °C

and 1 atm?
sodium (s) + water(l)------->sodium hydroxide (aq) + hydrogen(g)
Chemistry
1 answer:
Anastaziya [24]2 years ago
5 0

Answer:

44.8L of hydrogen gas

Explanation:

The reaction expression is given as:

            2Na   +  2H₂O   →    2NaOH    +  H₂

Given parameters:

Mass of sodium  = 92.4g

Unknown:

Volume of hydrogen gas  =  ?

Solution:

To solve this problem:

            1 mole of a substance at STP occupies a volume of  22.4L

Let us find the number of moles of the hydrogen gas;

 Number of moles of Na = \frac{mass}{molar mass}  

      Molar mass of Na = 23g/mol

 Number of moles  = \frac{92.4}{23}    = 4.02mole

From the balanced reaction expression:

       2 mole of Na will produce 1 mole of hydrogen gas

     4.02 mole of Na will produce \frac{4.02}{2}   = 2mole of hydrogen gas

So

         1 mole of a substance at STP occupies a volume of  22.4L

        2 mole of hydrogen gas will occupy a volume of 2 x 22.4  = 44.8L of hydrogen gas

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Isotope Atomic Mass (amu) Percent Abundance
exis [7]

Answer:

The average atomic mass is closer to Si- 28 because this isotope is present in more percentage in the sample.

Explanation:

Given data:

Atomic mass of silicon= ?

Percent abundance of Si-28 = 92.21%

Atomic mass of Si-28 = 27.98 amu

Percent abundance of Si-29 = 4.70%

Atomic mass of  Si-29 = 28.98 amu

Percent abundance of Si-30 = 3.09%

Atomic mass of  Si-30 = 29.97 amu

Solution:

Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)+(abundance of 2nd isotope × its atomic mass)  / 100

Average atomic mass = (92.21×27.98)+(4.70×28.98)+(3.09×29.97) /100

Average atomic mass =  2580.04 +136.21+92.61 / 100

Average atomic mass = 2808.86 / 100

Average atomic mass  = 28.08amu.

The average atomic mass is closer to Si- 28 because this isotope is present in more percentage in the sample.

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A b c , i think ...
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Mole of 46.6 g AgCl produced = 46.6/143.32 = 0.325 moles

Equivalent mole of NaCl = 0.325 moles.

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More on stoichiometric calculations can be found here: brainly.com/question/27287858

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