Answer:
44.8L of hydrogen gas
Explanation:
The reaction expression is given as:
2Na + 2H₂O → 2NaOH + H₂
Given parameters:
Mass of sodium = 92.4g
Unknown:
Volume of hydrogen gas = ?
Solution:
To solve this problem:
1 mole of a substance at STP occupies a volume of 22.4L
Let us find the number of moles of the hydrogen gas;
Number of moles of Na =
Molar mass of Na = 23g/mol
Number of moles = = 4.02mole
From the balanced reaction expression:
2 mole of Na will produce 1 mole of hydrogen gas
4.02 mole of Na will produce = 2mole of hydrogen gas
So
1 mole of a substance at STP occupies a volume of 22.4L
2 mole of hydrogen gas will occupy a volume of 2 x 22.4 = 44.8L of hydrogen gas
Answer: 0.055 moles of are produced by the reaction of 0.055 mol of ammonium perchlorate.
Explanation:
The balanced chemical reaction for decomposition of ammonium perchlorate is:
According to stoichiometry :
2 moles of produce = 2 moles of
Thus 0.055 moles of will produce =
of
Thus 0.055 moles of are produced by the reaction of 0.055mol of ammonium perchlorate.
Answer:
The answer to your question is 25.9 g of KCl
Explanation:
Data
Grams of KCl = ?
Volume = 0.75 l
Molarity = 1 M
Formula
Solve for number of moles
Substitution
Number of moles = 1 x 0.75
Simplification
Number of moles = 0.75 moles
Molecular mass KCl = 39 + 35.5 = 34.5
Use proportions to find the grams of KCl
34.5 g of KCl ---------------- 1 mol
x ---------------- 0.75 moles
x = (0.75 x 34.5) / 1
x = 25.9 g of KCl