A weight of 8.7 N is attached to a spring that has a spring constant of 190 N/m. How much will the spring stretch?
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Answer:- .
Explanation:- Atomic number for fluorine(F) is 9 and it's electron configuration is .
is formed when F loses one electron from it's valence shell.
Second shell is the valence shell for fluorine and so it loses one electron from 2p to form and the electron configuration of the ion becomes
.