Answer:
The combinations of gametes that could be produced from heterozygous individuals for both traits are PT, Pt, pT and pt.
Explanation:
An individual is heterozygous for two traits, flower color and stem height, with a PpTt (dihybrid) genotype and a phenotype showing the dominant traits, purple flowers and tall stem.
The genes of this individual for the above-mentioned traits contain different alleles, and taking into account the independent segregation of characters, the alleles present in its gametes could be:
- <em>Both dominant alleles: PT
</em>
- <em>One dominant and one recessive allele Pt or pT
</em>
- <em>Both recessive alleles: pt
</em>
Therefore, the traits of its offspring will depend on the alleles for those traits present in the gamete to which they are combined.
The answer is; B
Sometimes winds carry the sand of the beaches causing erosion. The fences act as breakers of this wind erosion. As wind tries to carry the sand, they encounter the fence and 'break'. Therefore, the sand is deposited along the fence forming a sand dune. These dunes also form protection from storm surges.
Answer: Positive charge of 1
Explanation: This is because it is believed that it is from the charge of the quarks that make up the nucleons which are protons and neutrons.
Answer:
Uno de los progenitores es heterocigoto para color naranja (Nn) y el otro parental es homocigoto recesivo para gris (nn). Al haber una cruza entre un homocigoto recesivo y un heterocigoto, la 50% de la progenie expresa color naranja (Nn), mientras que el otro 50% expresa color gris (nn).
Explanation:
<u>Datos disponibles:</u>
- Cruce entre peces naranjas y peces grises
- 50% de la F1 son peces grises
- Naranja dominante sobre gris
Podemos nombrar el alelo dominante para color naranja <em>N</em>, y al alelo recesivo para color gris <em>n</em>.
Para que en un cruce entre dos fenotipos distintos, el 50% de la primer camada exprese uno de estos fenotipos, entonces uno de los parentales debe ser heterocigoto, mientras que el otro parental debe ser homocigoto recesivo. De esta forma 50% de la primera generación expresara uno de los fenotipos, mientras que el otro 50% expresará el otro fenotipo.
Supongamos que uno de los parentales lleva el genotipo <em>Nn</em>, y el otro parental es <em>nn</em>.
Cruce:
Parental) Nn x nn
Gametas) N n n n
Fenotipos) Naranja Gris
Cuadro de Punnett) N n
n Nn nn
n Nn nn
F1) 2/4 = 1/2 = 50% de la progenie tendrá genotipo heterocigoto, Nn
2/4 = 1/2 = 50% de la progenie tendrá genotipo homocigota recesivo,
nn
50% de la progenie será color naranja (Nn)
50% de la progenie será color gris (nn)
It makes it own food that why its called an AUTOtroph
