The Lorentz force exerted on a charge moving in a magnetic field is given by:
where
q is the charge
v is the speed of the charge
B is the intensity of the magnetic field
is the angle between the directions of the field and of the velocity
The data we have in our problem are:
If we substitute these data and we rearrange the initial equation, we can calculate the speed of the particle:
so, the correct answer is
<span>1.1 × 104 m/s</span>
Answer:
He barely makes it but hit his leg on the pool edge.
Explanation:
Using kinematic formula: Δx=
We can plug in delta x, v zero, and acceleration.
delta x = 8 meters, v0 = 0. a = 9.8
8=(1/2)9.8*t^2
Around 1.278 seconds of airtime.
4 * 1.278 = 5.112 meters horizontally assuming no air resistance
That was close!
Because the switch isn’t connected to the wire, so the electric charges that is going through the wire isn’t reaching both sockets for the lightbulb.
1,000 W = 1 kW
100 W = 0.1 kW
(0.1 kW) x (6 h) = 0.6 kWh <=== energy
(0.6 kWh) x (£0.1359/kWh) = £0.0815 <=== cost of it
Answer:
v = 6.45 10⁻³ m / s
Explanation:
Electric force is
F = q E
Where q is the charge and E is the electric field
Let's use Newton's second law to find acceleration
F- W = m a
a = F / m - g
a = q / m E g
Let's calculate
a = -1.6 10⁻¹⁹ / 9.1 10⁻³¹ (-1.30 10⁻¹⁰) - 9.8
a = 0.228 10² -9.8
a= 13.0 m / s²
Now we can use kinematics, knowing that the resting parts electrons
v² = v₀² + 2 a y
v =√ (0 + 2 13.0 1.6 10⁻⁶)
v = 6.45 10⁻³ m / s