Answer:
Exfoliation or Unloading. As upper rock portions erode, underlying rocks expand. ...
Thermal Expansion. Repeated heating and cooling of some rock types can cause rocks to stress and break, resulting in weathering and erosion. ...
Organic Activity. ...
Frost Wedging. ...
Crystal Growth.
Explanation:
Answer:
100 J
Explanation:
From the question, The work done by the forces in moving the box is given as
W = FxdcosФ+Fydcosα................... Equation 1
Where W = Work done, Fx = force acting parallel to the floor, d = distance moved by the box, Ф = angle the parallel force makes with the floor, Fy = force acting perpendicular to the floor, α = angle the perpendicular force make with the floor.
Give: Fx = 10 N, d = 20 m, Fy = 5 N, Ф = 0°, α = 90°
Substitute into equation 1
W = 10×10×cos0°+5×20×cos90°
W = 10×10×1+0
W = 100 J.
Note: The work done by the perpendicular force is zero
Hence the work done = 100 J
Answer:its B
Explanation:
The suns gravity keeps the planets in their gravitational orbit.
Answer:
a) Posición y velocidad después de los 6s
i) Posición = -26.58m
ii) velocidad = -33.86m/s
b) Tiempo para alcanzar la altura máxima
= 2.55s
c) Alcance horizontal
= 220.7m
Explanation:
a) Posición y velocidad después de los 6s
i) Posición
y = (usinθ)t – 1/2 gt²
u = 50m/s
θ = 30°
g = 9.81m/s²
t = 6s
y = (50 × sin 30)6 - 1/2 × 9.81 × 6²
y = 150 - 176.58
y = -26.58m
ii) velocidad
v = u sinθ–gt
u = 50m/s
θ = 30°
g = 9.81m/s²
t = 6s
v = 50 × sin 30 - 9.81 × 6
v = 25 - 58.86
v = -33.86m/s
b) Tiempo para alcanzar la altura máxima
usinθ /g
u = 50m/s
θ = 30°
g = 9.81m/s²
= 50 × sin 30/ 9.81
= 25/9.81
= 2.5484199796s
≈ 2.55s
c) Alcance horizontal
R = u²sin2θ/g
u = 50m/s
θ = 30°
g = 9.81m/s²
R = 50² ×( sin 2 ×30°) /9.81
R = 220.69964419m
≈ 220.7m
Answer:
Explanation:
v² = u² + 2as
v = 0
u = 96 / 3.6 = 26.7 m/s
0² = 26.7² + 2a100
a = -3.5555555... ≈ -3.6 m/s²
the negative sign indicated the acceleration vector opposes the (assumed positive) initial velocity vector direction.
