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sasho [114]
3 years ago
13

Where do we consider the Universal Gravitational Constant?

Physics
1 answer:
nlexa [21]3 years ago
7 0

A anywhere in the universe

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What would we do if we didn't have solar energy?
Anvisha [2.4K]

We would have to use wind or another source

8 0
3 years ago
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Susie rides down and to the right on a slide for a total displacement of -3m at an angle of 45 degrees above the ground. What wa
Svetlanka [38]

Susie's vertical displacement is 2.1 m

Explanation:

In order to solve this problem, we have to resolve the displacement vector along the vertical direction.

The vertical component of a vector is given by:

v_y = v sin \theta

where

v is the magnitude of the vector

\theta is the angle between the direction of the vector and the horizontal

Therefore, the vertical  component of the displacement in this problem is given by

d_y = d sin \theta

where

d = 3 m is the magnitude of the displacement

\theta=45^{\circ} is the angle between the  displacement and the horizontal

Substituting, we find

d_y = (3)(sin 45^{\circ})=2.1 m

Learn more about vector components:

brainly.com/question/2678571

#LearnwithBrainly

6 0
4 years ago
on the surface of planet x a body with a mass of 10 kilograms weighs 40 newtons. The magnitude of the acceleration due to gravit
tamaranim1 [39]
Based on the Newton's second law of motion, the value of the net force acting on the object is equal to the product of the mass and the acceleration due to gravity. If we let a be the acceleration due to gravity, the equation that would allow us to calculate it's value is,
      W = m x a
where W is weight, m is mass, and a is acceleration. Substituting the known values,
    40 kg m/s² = (10 kg) x a
Calculating for the value of a from the equation will give us an answer equal to 4. 
ANSWER: 4 m/s². 

6 0
3 years ago
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Just after a motorcycle rides off the end of a ramp and launches into the air, its engine is turning counterclockwise at 8325 re
alexgriva [62]

Answer:

\frac{Ie}{lm} = 1.10*10^{-3}

Explanation:

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ratio of moment of inertia of engine to motorcycle is given as

\frac{Ie}{lm} = \frac{-N}{(nf-ni)}

\frac{Ie}{lm} = \frac{-(-4.2)}{(12125 - (8325))}

\frac{Ie}{lm} = 1.10*10^{-3}

5 0
4 years ago
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A 55.2 kg softball player moving 3.11 m/s slides across dirt with uk=0.310. How far does she slide before coming to a stop​
hoa [83]

Refer to the attachment

5 0
3 years ago
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