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3 years ago

Why is having to much fat , or too little fat, a potentially serious health problem?

1 answer:

7 0

Too much fat could result in heart conditions or some other serious health problems. Too little could cause your body to go into "starvation mode" and take nutrients from your muscles (deteriorating your muscles) to make up for what it's lacking.

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________ Layer of the atmosphere where jets fly through and contains ozone layer

ratelena [41]

Answer:

stratosphere

Explanation:

the stratosphere is the second major layer of the atmosphere just above the troposphere, it has its lower area to be cooler and higher area to be warmer due to the ozone layers absorption of ultraviolet rays. It is also the layers which planes fly through because it is stable.

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3 years ago

Use the drop-down menus to explain how noise cancellation works. Waves with similar are created to interfere with unwanted sound

leonid [27]

Amplitudes, and Crests

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3 years ago

Read 2 more answers

Meher is riding a bicycle on a slope. explain the different motions taking place during this time

gtnhenbr [62]

Answer:

Mehar cant ride down the slope

Explanation:

She does not has a bicycle

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3 years ago

Newtons third lawWhat action-reaction forces are involved when a rocket engine fires? Why doesnt a rocket need air to push on? A

dangina [55]

Answer: action forc roketorce

reaction force is engine fires

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3 years ago

A capacitor is charged until it holds 5.0 j of energy. it is then connected across a 10-kω resistor. in 13.6 ms , the resistor d

prohojiy [21]

Answer:

The capacite is C=5.32 uF using the equations of voltage and energy in capacitance

Explanation:

The energy holds is 5 J and the resistor dissipates 2J so the energy total is 3J

Using:

$V_{t}= V_{o}e^{\frac{-t}{R*C} }$

Voltage in this case is the energy dissipated so

$E_{t}= E_{o}e^{\frac{-t}{R*C} }$

$\frac{\sqrt{E_t} }{\sqrt{E_o} } = e^{\frac{-t}{R*C} }$

$\frac{\sqrt{3 J} }{\sqrt{5J} } = e^{\frac{-13.6ms}{10kw*C} }$

Using the equation to find capacitance

$ln 0.775= e^{\frac{-13.6 x10^{3} }{10x10^{3}*C }} \\ln(0.775)= ln * e^{\frac{-13.6 x10^{3s} }{10x10^{3}*C }} \\\\ln(0.775)= {\frac{-13.6 x10^{3} }{10x10^{3}*C }} \\C= \frac{-13.6 x10^{-3} }{10x10x^{3}*ln(0.775) }$

$C= 5.32x10^{-6}$ F

C= 5.32 uF because u is the symbol for micro that is equal to $10^{-6}$

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3 years ago