Given that,
Mass of trackler, m₁ = 100 kg
Speed of trackler, u₁ = 2.6 m/s
Mass of halfback, m₂ = 92 kg
Speed of halfback, u₂ = -5 m/s (direction is opposite)
To find,
Mutual speed immediately after the collision.
Solution,
The momentum of the system remains conserved in this case. Let v is the mutual speed after the collision. Using conservation of momentum as :
So, the mutual speed immediately after the collision is 1.04 m/s but in opposite direction.
15 min
Explanation:
take 0.25 and put it in for 1.00 and you will see its 0.25 but when you add it all 4 times it is 1.00 so then you would take that and do it to the hour ... how many times does four go into 60
Momentum = (mv).
<span>(2110 x 24) = 50,640kg/m/sec. truck momentum. </span>
<span>Velocity required for car of 1330kg to equal = (50,640/1330), = 38m/sec</span>
Decreasing the distance between two objects having a considerable mass would increase the attraction on gravitation. The reverse is true that if you separate or inrease the objects distance would substantially decrease their gravitational attraction. Most object in our planet is held by its gravitational force towards it's center.
<span>The answer is a heterogeneous mixture. Mixtures can be homogeneous and heterogeneous. If a solid and a liquid of a mixture cannot be separated and the difference between them is not visible, it is called homogeneous mixture (or solution). If a solid and a liquid of a mixture are visible and can be separated easily, the mixture is called heterogeneous.</span>
