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1 year ago

If you jog for 1 hr and travel 10 km, the calculation of 10 km/hr describes your.

Physics

1 answer:

zloy xaker [14]1 year ago

8 0

Answer:

[Speed] or [Velocity (if there is a direction)]

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I have to draw a wave on a separate sheet of paper given the following measurements down below. I'm a bit confused, do I just us

Alex73 [517]

You have to draw a mathematical spatial axes .in order to judge is it right or not .. well you have to draw the crest and trough both of 1 cm in length and the total wavelength (same phase on the wave of 2 cm ) something like this

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3 years ago

When a plant is entering the calvin cycle of photosythesis______.

Korolek [52]

The Calvin cycle<span> refers to the light-independent reactions in photosynthesis that take place in three key steps. Although the </span>Calvin Cycle<span> is not directly dependent on light, it is indirectly dependent on light since the necessary energy carriers (ATP and NADPH) are products of light-dependent reactions.

So basically it indirectly needs the light, even it's called light-independant reaction.

So the answer is the last one.</span>

5 0

3 years ago

Read 2 more answers

Five different forces act on an object. Is it possible for the net force on the object to be zero?

bazaltina [42]

No because there must be an even # if their is an even amount one of the forces isn’t being cancelled

4 0

2 years ago

Car A hits car B (initially at rest and of equal mass) from behind while going 15 m/s Immediately after the collision, car B mov

Mamont248 [21]

Given :

Initial speed of car A is 15 m/s and initial speed of car B is zero.

Final speed of car A is zero and final speed of car B is 10 m/s.

To Find :

What fraction of the initial kinetic energy is lost in the collision.

Solution :

Initial kinetic energy is :

$K.E_i = \dfrac{15^2m}{2} + 0\\\\K.E_i = \dfrac{225 m}{2}$

Final kinetic energy is :

$K.E_f = \dfrac{10^2m}{2} + 0\\\\K.E_f = \dfrac{100m}{2}$

Now, fraction of initial kinetic energy loss is :

$Loss = \dfrac{\dfrac{225m}{2}-\dfrac{100m}{2}}{\dfrac{100m}{2}}\\\\Loss = \dfrac{125}{100}\\\\Loss = 1.25$

Therefore, fraction of initial kinetic energy loss in the collision is 1.25 .

6 0

2 years ago

Ask Your Teacher A basketball player shoots toward a basket 5.8 m away and 3.0 m above the floor. If the ball is released 1.7 m

const2013 [10]

Answer:

The answer to your question is vo = 5.43 m/s

Explanation:

Data

distance = d= 5.8 m

height = 3 m

height 2 = 1.7 m

angle = 60°

vo = ?

g = 9.81 m/s²

Formula

hmax = vo²sinФ/ 2g

Solve for vo²

vo² = 2ghmax / sinФ

Substitution

vo² = 2(9.81)(3 - 1.7) / 0.866

Simplification

vo² = 19.62(1.3) / 0.866

vo² = 25.51 / 0.866

vo² = 29.45

Result

vo = 5.43 m/s

5 0

3 years ago