The area of the entire sector of DEF = 60 / 360 * PI * radius^2
sector area = 1 / 6 * 3.14159265... * 20^2
sector area =
<span>
<span>
<span>
209.4395102393
</span>
</span>
</span>
segment area = sector area - triangle DEF Area
triangle DEF Area = (1/2) * 20 * sine 60 * 20
triangle DEF Area = (1/2) * 0.86603 * 400
triangle DEF Area = <span><span><span>(1/2) * 346.412
</span>
</span>
</span>
triangle DEF Area =
<span>
<span>
<span>
173.206
</span>
</span>
</span>
segment area = <span>
<span>
209.4395102393
</span>
-173.206
</span>
segment area =
<span>
<span>
<span>
36.2335102393
</span>
</span>
</span>
segment area =
36.23 m
Source:
http://www.1728.org/circsect.htm
Answer:
The product is 1.05
another pair of factors with the same product are 6/10 x 14/8
Answer:
k=10
Step-by-step explanation:
4k + 12= 52
minus 12 on both sides
4k=40
now divide by 4
k=10
Answer:
Step-by-step explanation:
Samantha needs 4/5 yard of fabric to make costumes for the school play.
Let x represent the number of yards of fabric that she has
Let y represent the total number of costumes that she can make from x yards of fabric.
Since one costume require 4/5 yards of fabric, y costumes will require
x ÷ 4/5 = x×5/4 = 5x/4
The equation will be
y = 5x/4
to find how many costumes she can make with 8 yards of fabric, it becomes
y = (5×8)/4
y = 40/4 = 10
