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NISA [10]
3 years ago
10

A fourth-grade teacher wants to ensure students understand the life cycle process of plants. The teacher decides to incorporate

the science-as-inquiry standard from the National Education Science Standards. How can the teacher achieve the specified learning outcome?
Physics
1 answer:
Annette [7]3 years ago
4 0

Answer:

There are several options that the teacher can use to incorporate the concept into students' understanding.

Explanation:

1. The students can draw all the plants that they know.

2. Children can be asked to bring the flowers to school so that they can identify the plants themselves.

3. The children can plat the flowers in makeshift pots and then take the best plants and transplant them in the garden or elsewhere.

4. The children can take occasional trips and observe and record any changes to the plants.

4. The teacher can ask the students to draw the flowers and emphasize on the productive parts like the stamens, leaves, pistils, stems.  

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10. According to Newton's First Lawy , if a box is pushed with no external resistance, what will the action of the box be ?
kati45 [8]

Explanation:

According to Newton's First Law of motion, if a box is pushed with no external resistance, the box will keep on moving due to the absence of external force. It might gets stopped due to frictional force that is acting between the surface and the ball. The first law of motion is also known as law of inertia. the magnitude of force acting on the object is given by second law of motion.

4 0
3 years ago
Read 2 more answers
The formula v = √2.5r models the maximum safe speed, v, in miles per hour, at which a car can travel on a curved road with radiu
mel-nik [20]

Answer:

The maximum safe speed of the car is 30.82 m/s.

Explanation:

It is given that,

The formula that models the maximum safe speed, v, in miles per hour, at which a car can travel on a curved road with radius of curvature r r, is in feet is given by :

v=\sqrt{2.5\ r}.........(1)

A highway crew measures the radius of curvature at an exit ramp on a highway as 380 feet, r = 380 feet

Put the value of r in equation (1) as :

v=\sqrt{2.5\ \times 380}

v = 30.82 m/s

So, the maximum safe speed of the car is 30.82 m/s. Hence, this is the required solution.

4 0
3 years ago
A particle with charge − 2.74 × 10 − 6 C −2.74×10−6 C is released at rest in a region of constant, uniform electric field. Assum
s2008m [1.1K]

Answer:

241.7 s

Explanation:

We are given that

Charge of particle=q=-2.74\times 10^{-6} C

Kinetic energy of particle=K_E=6.65\times 10^{-10} J

Initial time=t_1=6.36 s

Final potential difference=V_2=0.351 V

We have to find the time t after that the particle is released and traveled through a potential difference 0.351 V.

We know that

qV=K.E

Using the formula

2.74\times 10^{-6}V_1=6.65\times 10^{-10} J

V_1=\frac{6.65\times 10^{-10}}{2.74\times 10^{-6}}=2.43\times 10^{-4} V

Initial voltage=V_1=2.43\times 10^{-4} V

\frac{\initial\;voltage}{final\;voltage}=(\frac{initial\;time}{final\;time})^2

Using the formula

\frac{V_1}{V_2}=(\frac{6.36}{t})^2

\frac{2.43\times 10^{-4}}{0.351}=\frac{(6.36)^2}{t^2}

t^2=\frac{(6.36)^2\times 0.351}{2.43\times 10^{-4}}

t=\sqrt{\frac{(6.36)^2\times 0.351}{2.43\times 10^{-4}}}

t=241.7 s

Hence, after 241.7 s the particle is released has it traveled through a potential difference of 0.351 V.

6 0
3 years ago
What property do all three of these common household substances have in common?
Oxana [17]

Answer:

whats the items

Explanation:

4 0
3 years ago
As you read this in your chair, how fast are you moving relative to the chair? relative to the sun?
Oliga [24]
To answer this question, you need to know the definition of Relative Motion:
 The motion is relative when it depends on a reference point or referencial system. If you know the reference point, you can determine the velocity of an object.
 If you are sitting on your chair, you are not moving relative to it (Your speed is 0 km/s); but as you know, our planet moves around the Sun (Traslation Movement) with a speed of 30.0 km/s. Therefore, you are moving 30.0 km/s relative to the sun.
5 0
3 years ago
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