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NISA [10]
3 years ago
10

A fourth-grade teacher wants to ensure students understand the life cycle process of plants. The teacher decides to incorporate

the science-as-inquiry standard from the National Education Science Standards. How can the teacher achieve the specified learning outcome?
Physics
1 answer:
Annette [7]3 years ago
4 0

Answer:

There are several options that the teacher can use to incorporate the concept into students' understanding.

Explanation:

1. The students can draw all the plants that they know.

2. Children can be asked to bring the flowers to school so that they can identify the plants themselves.

3. The children can plat the flowers in makeshift pots and then take the best plants and transplant them in the garden or elsewhere.

4. The children can take occasional trips and observe and record any changes to the plants.

4. The teacher can ask the students to draw the flowers and emphasize on the productive parts like the stamens, leaves, pistils, stems.  

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In an early attempt to understand atomic structure, Niels Bohr modeled the hydrogen atom as an electron in uniform circular moti
AleksandrR [38]

Answer:

The answer is below

Explanation:

Using Coulomb's law of electric field which is:

F=k\frac{q_1q_1}{r^2}\\\\ k =constant=9*10^9\ Nm^2/C^2,q_1=q_2=1.6*10^{-19}C,r=5.29*10^{-11}m\\\\Substituting\ gives:\\\\F=9*10^9*\frac{(1.6*10^{-19})*(1.6*10^{-19})}{(5.29*10^{-11})^2} =8.22*10^{-8}N\\\\Both\ centripetal\ force\ is\ given\ by:\\\\F=m\frac{v^2}{r} \\\\m = mass\ of \ electron=9.11*10^{-31}g,v=speed\ of\ electron\\\\F=m\frac{v^2}{r} \\\\v=\sqrt{\frac{F*r}{m} } \\\\subsituting:\\\\v=\sqrt{\frac{8.22*10^{-8}*5.29*10^{-11}}{9.11*10^{-31}} } \\\\v=2.18*10^6\ m/s\\\\

But\ \omega=\frac{v}{r}=\frac{2.18*10^6}{5.29*10^{-11}}  =4.13*10^{17}\\\\\omega=2\pi f; f=frequency\\\\f=\frac{\omega}{2\pi} =\frac{4.13*10^{17}}{2\pi} \\\\f=6.57*10^{15}\ Hz

6 0
3 years ago
Memories
nevsk [136]

Answer:

Its ok but the answer is C

Explanation:

7 0
3 years ago
A beam of light with a wavelength 760 nm in air travels in water. The index of refraction of water is 1.33. What is the waveleng
BabaBlast [244]

Answer:

<em>The wavelength of water = 571.43 nm</em>

Explanation:

Refractive index of water = wave length of light in air/wave length of light in water

R.d = λ₁/λ₂.................. Equation 1

making λ₂ the subject of equation 1

λ₂ = λ₁/R.d...................... Equation 2

R.d = refractive index of water , λ₁ = wave length of light in air, λ₂ = wave length of light in water

<em>Given: R.d = 1.33, λ₁ = 760nm</em>

<em>Substituting these values into equation 2</em>

λ₂  = 760/1.33

<em>λ₂  = 571.43 nm</em>

<em>Therefore the wavelength of water = 571.43 nm</em>

6 0
3 years ago
The half-life of a certain element is 100 days. How many half-lives will it be before only one-eighth of this element remains?
Natalka [10]

Answer:

3

Explanation:

The half-life is the time it takes for the amount of radioactive isotope to halve. Therefore, we have:

- After 1 half-life, only 1/2 of the element will be left

- After 2 half-lives, only 1/4 of the element will be left

- After 3 half-lives, only 1/8 of the element will be left

So, it will take 3 half-lives for the element to become 1/8 of its original amount.

Mathematically, this can be also verified by using the equation

\frac{N(t)}{N_0}=(\frac{1}{2})^\frac{t}{\tau_{1/2}}

where

N(t) is the amount of the element left at time t

N0 is the initial amount of the element

\tau_{1/2} is the half-life

Substituting t=3\tau_{1/2} (3 half-lives), we find

\frac{N(t)}{N_0}=(\frac{1}{2})^3=\frac{1}{8}

7 0
3 years ago
A Cessna 172 aircraft must reach a speed of 35 m/s for takeoff. How long of a runway is needed if the acceleration of the aircra
vodomira [7]
this should be the answer to your question

7 0
4 years ago
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