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inessss [21]
3 years ago
12

The Sun is only an average sized star. Why does it appear so much brighter than any other star?

Physics
1 answer:
aivan3 [116]3 years ago
8 0

Because it's so much closer to us than any other star.

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During what intervals was jenny negatively accelerating
PolarNik [594]

Jenny's acceleration was negative during the intervals of time when her speed was decreasing.

That's really all we can tell, because you really haven't given us any information except her name.

5 0
4 years ago
What happens to a light wave when it travels from air glass?
iVinArrow [24]
Its speed decreases, its wavelength increases, and its frequency Remains the Same.
5 0
4 years ago
Three fire hoses are connected to a fire hydrant. Each hose has a radius of 0.017 m. Water enters the hydrant through an undergr
alexira [117]

Answer:

2.36 x 10^5 kg

Explanation:

radius of hose, r = 0.017 m

radius of underground pipe, R = 0.088 m

number of hoses, n = 3

velocity of water in underground pipe, V = 2.7 m/s

Let v is the velocity of water in each hose.

According to the equation of continuity

A x V = n x a x v

π R² x V = n x π x r² x v

0.088 x 0.088 x 2.7 = 3 x 0.017 x 0.017 x v

v = 24.12 m/s

(a) Amount of water poured onto a fire in one hour by all the three hoses              

                    = n x a x v x density of water x time

                    = 3 x 3.14 x 0.017 x 0.017 x 24.12 x 1000 x 3600

                    = 2.36 x 10^5 kg

Thus, the amount of water poured onto the fire in one hour is 2.36 x 10^5 kg.

6 0
3 years ago
Which of the following is an example of an electromagnetic wave ?
Alex

Answer:

Its a wave

Explanation:

THis is one

3 0
3 years ago
Read 2 more answers
Two protons in a molecule are 4.40 10-10 m apart. Find the electric force exerted by one proton on the other.
Akimi4 [234]

Answer:

F = 1.19 x 10⁹ N

Explanation:

The electrostatic force between the charged particles is given by Colomb's Law as follows:

F = \frac{kq_{1}q_{2}}{r^{2}}

where,

F = Electrostatic force = ?

k = Colomb's constant = 9 x 10⁹ N.m²/C²

q₁ = q₂ = charge on proton = 1.6 x 10⁻¹⁹ C

r = distance between protons = 4.4 x 10⁻¹⁰ m

Therefore,

F = \frac{(9\ x\ 10^{9}\ Nm^{2}/C^{2})(1.6\ x\ 10^{-19}\ C)(1.6\ x\ 10^{-19}\ C)}{(4.4\ x\ 10^{-10})^{2}} \\\\

<u>F = 1.19 x 10⁹ N</u>

8 0
3 years ago
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