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Andreas93 [3]
3 years ago
8

What occurs when an unstable atomic nucleus changes into other nuclei by emitting particles and energy

Physics
1 answer:
Klio2033 [76]3 years ago
6 0
I'm not too sure but I think it's nuclear decay
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If the distance d (in meters) traveled by an object in time t (in seconds) is given by the formula d=a+bt2, the si units of a an
ss7ja [257]
Distance , d = a+bt^2

The unit of d is in meter and t is in seconds.

So the unit of a a must be meter.

Now we have unit of bt^2 is meter.

So unit of b*second^2 = meter

Unit of b = meter/second^2

So unit of a = m and unit of b = m/s^2.
8 0
3 years ago
What can be inferred when an atom is electrically charged?
Elena-2011 [213]

When an atom becomes electrically charged the number of electrons or protons stops and they are not equal again. The "extra" electron or proton is not balanced by something inside the atom any longer and it starts attracting itself to othet protons or electrons in other atoms.

<h3>What is atomic structure?</h3>

An atomic structure comprises of positively charged nucleus which is surrounded by negatively charged particles called electron and neutron which is neutral charged.

Unlike charges attract each other while like charges repel each other.

Therefore, When an electron is fully charged, the number of electrons will stop to be unequal again.

Learn more about Atomic charge here.

brainly.com/question/18102056

7 0
2 years ago
The spring to launch a pinball in a pinball machine is compressed 25 cm and has a spring constant of 140 N/m.
mote1985 [20]

Answer:

I think it is 5.6. This is my answer

8 0
3 years ago
an object 24.0 cm from a concave mirror creates a virtual image at -33.5 cm. if the image is 7.25 cm tall, what is the height of
Hitman42 [59]

The height of the object will be -5.19 cm

A concave mirror's reflecting surface curves inward and away from the light source. Light is reflected inward to a single focus point via concave mirrors. Concave mirrors, in contrast to convex mirrors, produce a variety of images depending on the object's to the mirror.

Given an object 24.0 cm from a concave mirror creates a virtual image at -33.5 cm. if the image is 7.25 cm tall

So let,

v =  Image distance from the mirror = -33.5 cm

u = object distance from the mirror (concave) = 24 cm

hi = Image height = 7.25 cm

h = height of the object = ?

Using below formula to find height of the object

-v/u = hi/h

Putting all value in the formula we get

-(-33.5)/(-24) = 7.25/h

h = -5.19 cm

Therefore the height of the object will be -5.19 cm

Learn more about Concave mirror here:

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#SPJ10

3 0
2 years ago
You go to the hardware store to buy a new 50 ft garden hose. You find you can choose between hoses of ½ inch and 5/8 inch inner
omeli [17]

To solve this problem it is necessary to consider two concepts. The first of these is the flow rate that can be defined as the volumetric quantity that a channel travels in a given time. The flow rate can also be calculated from the Area and speed, that is,

Q = V*A

Where,

A= Cross-sectional Area

V = Velocity

The second concept related to the calculation of this problem is continuity, which is defined as the proportion that exists between the input channel and the output channel. It is understood as well as the geometric section of entry and exit, defined as,

Q_1 = Q_2

V_1A_1=V_2A_2

Our values are given as,

A_1=\frac{1}{2}^2*\pi=0.785 in^2

A_2=\frac{5}{8}^2*\pi=1.227 in^2

Re-arrange the equation to find the first ratio of rates we have:

\frac{V_1}{V_2}=\frac{A_2}{A_1}

\frac{V_1}{V_2}=\frac{1.227}{0.785}

\frac{V_1}{V_2}=1.56

The second ratio of rates is

\frac{V2}{V1}=\frac{A_1}{A2}

\frac{V2}{V1}=\frac{0.785}{1.227}

\frac{V2}{V1}=0.640

3 0
3 years ago
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