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3 years ago

Just kill meh now pls

Physics

2 answers:

MArishka [77]3 years ago

8 0

Answer:

pollution, mineral location, and new energy sources.

Explanation:

Alina [70]3 years ago

4 0

Answer:

B. pollution, mineral location, and new energy sources

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A bullet was fired from a gun. The bullet had a mass of 50g and the kinetic energy of the bullet was 25 kJ. How fast did it go?

Elenna [48]

Answer:

$given \: \\ mass \: (m) = 50g \\ kinetic \: enegy \: (k.e) = 25kj \\ velocity(v) = x \\ form \\ k.e = \frac{1}{2} \times MV ^{2} \\ 25 = \frac{1}{2} \times 50 \times v {}^{2} \\ 25 = 25 \times v {}^{2} \\ v {}^{2} = \frac{25}{25} \\ v {}^{2} = 1 \\ v = \sqrt{1} \\ v = 1ms {}^{ - }$

the car it go fast with velocity 1m/s

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3 years ago

What is the approximate diameter of an inflated

antiseptic1488 [7]

The approximate diameter of an inflated basketball is <span>2 × 10^–2 m. The answer is number 1. The rest of the choices do not answer the question above because they are too big for the diameter of the basketball.</span>

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4 years ago

What's cav-ins mean?

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If ur meaning cavins. a cavin is like a cave or a hollow route. idk if thats what ur asking?

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3 years ago

A car traveling at 27 m/s runs out of gas while traveling up a 8.0 ∘ slope. How far will it coast before starting to roll back d

Ad libitum [116K]

Answer:

Approximately $2.7 \times 10^{2}\; \rm m$ along the slope, assuming that no energy was lost to friction.

Explanation:

Let $v$ denote the initial velocity of this vehicle. Let $m$ denote the mass of this vehicle. The kinetic energy (KE) of this vehicle would have initially been:

$\displaystyle \frac{1}{2}\, m \cdot v^{2}$ .

The gain in the gravitational potential energy (GPE) of this vehicle is proportional to the increase in its height.

Let $g$ denote the gravitational field strength. $g \approx 9.81\; \rm m \cdot s^{2}$ on the earth. If the increase in the height of this vehicle is $h$ , this vehicle would have gained GPE:

$m \cdot g \cdot h$ .

Hence, the height of this vehicle is maximal when the GPE of this vehicle is maximized.

Since the vehicle went out of fuel, all its GPE would have been converted from KE. Assuming that no energy was converted to friction. The GPE of this vehicle would be maximal when the entirety of the KE was converted to GPE.

Hence, the maximal GPE of this vehicle would be equal to its initial KE:

$\displaystyle m \cdot g \cdot h = \frac{1}{2}\, m \cdot v^{2}$ .

The maximum height of this vehicle would be:

$\begin{aligned} h &= \frac{(1/2) \, m \cdot v^{2}}{m \cdot g}\\ &= \frac{v^{2}}{2\, g}\end{aligned}$ .

Given that $v = 27\; \rm m\cdot s^{-1}$ , the maximum height of this vehicle would be:

$\begin{aligned} & \frac{v^{2}}{2\, g} \\ =\; & \frac{(27\; \rm m\cdot s^{-1})^{2}}{2 \times 9.81\; \rm m\cdot s^{-2}} \\ \approx \; &37.2\; \rm m\cdot s^{-1}\end{aligned}$ .

Refer to the diagram attached. The distance that this vehicle traveled along the slope would be approximately:

$\begin{aligned}\frac{37.2\; \rm m}{\sin(8.0^{\circ})} \approx 2.7 \times 10^{2}\; \rm m\end{aligned}$ .

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3 years ago

When you heat water on a stove, how does its energy change?

olasank [31]

Answer:

tthe body of what it is supplied in its temperature rises

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