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3 years ago

What is the approximate diameter of an inflated

1 answer:

7 0

The approximate diameter of an inflated basketball is 2 × 10^–2 m. The answer is number 1. The rest of the choices do not answer the question above because they are too big for the diameter of the basketball.

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A plastic rod has been bent into a circle of radius R = 8.00 cm. It has a charge Q1 = +2.70 pC uniformly distributed along one-q

vovikov84 [41]

Answer:

Part a)

$V = -1.52 V$

Part b)

$V = -1.16 V$

Explanation:

Part a)

Electric potential is a scalar quantity

so here we can say that total potential due to a ring on its center is given as

$V = \frac{kQ}{R}$

here we know that

$Q = Q_1 - 6Q_1$

$Q = - 5 Q_1$

$Q_1 = 2.70 pC$

now we have

$V = \frac{(9\times 10^9)(-5\times 2.70 \times 10^{-12})}{0.08}$

$V = -1.52 V$

Part b)

Potential on the axis of the ring is given as

$V = \frac{kQ}{\sqrt{r^2 + R^2}}$

$V = \frac{(9\times 10^9)(-5\times 2.70\times 10^{-12})}{\sqrt{0.08^2 + 0.0671^2}}$

$V = -1.16 V$

8 0

3 years ago

The magnitude of the action potential is correlated with the strength of the stimulating input. True or False

Vesnalui [34]

Answer:

True

Explanation:

3 0

3 years ago

How long would it take a drag racer to increase her speed from 10m/s to 20 m/s if her car accelerates at a uniform rate of 15 m/

weeeeeb [17]

Answer:

t = 0.67 [s]

Explanation:

To solve this problem we must use the following kinematics equation.

$v_{f} =v_{i} +(a*t)\\where:$

Vf = final velocity = 20[m/s]

Vi = initial velocity = 10 [m/s]

a = aceleration = 15 [m/s^2]

Now replacing in the equation we have:

20 = 10 + (15*t)

t = (20-10)/15

t = 0.67 [s]

7 0

3 years ago

9) If, after viewing a specimen at low power, you switch to high-dry power and, after using fine focus, cannot find the specimen

xeze [42]

Answer:

See the answer below

Explanation:

The best thing one can do in this case would be to return the microscope's objective to low power and then re-center the specimen before switching back to high-dry power.

Most of the time, what makes the specimen under the microscope to be out of focus at higher objective powers after being in focus at low power is because they are not properly centered on the stage. Hence, before calling on the instructor, it would be wise to first return to low power, re-center the specimen and bring it into focus after which the high power objective can be returned to and the fine focus adjusted to bring the image back to focus.

After doing the above and the specimen still does not come into focus, then the instructor can be called upon.

4 0

3 years ago

Hydrogen and chlorine are pure substances , or

Dvinal [7]

Answer:

or pure hydrogen

Explanation:

hope this helps you because this is the answer i have for you

5 0

3 years ago

Read 2 more answers