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miskamm [114]
4 years ago
11

Suppose you were bungee jumping from a bridge while blowing a hand-held air horn. How would someone remaining on the bridge hear

the pitch of the air horn as time increased?
a. The pitch would get progressively lower (i.e., smaller frequency)

b. The pitch would get progressively higher (i.e., larger frequency)

c. The pitch would remain the same (i.e., constant frequency)
Physics
1 answer:
Readme [11.4K]4 years ago
6 0

Answer:

Answer to the question:

Explanation:

a. The pitch would get progressively lower (i.e., smaller frequency)

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TiliK225 [7]
(C) have the same heat capacity
3 0
3 years ago
Assume that the average mass of each of the approximately 1 billion people in China is 55 kg.Assume that they all gather in one
Harman [31]

Answer: 5.9(10)^{-8} m

Explanation:

The equation to calculate the center of mass C_{M} of a particle system is:

C_{M}=\frac{m_{1}r_{1}+m_{1}r_{1}+...+m_{n}r_{n}}{m_{1}+m_{2}+...+m_{n}}

In this case we can arrange for one dimension, assuming the geometric center of the Earth and the ladder are on a line, and assuming original center of mass located at the Earth's geometric center:

C_{M}=\frac{m_{E}(0 m) + m_{p} r_{E-p}}{m_{E}+m_{p}}

Where:

m_{E}=5.9(10)^{24} kg is the mass of the Earth

m_{p}=55(10)^{9} kg is the mass of 1 billion people

r_{E}=6371000 m is the radius of the Earth

r_{E-p}=6371000 m- 2m=6370998 m is the distance between the center of the Earth and the position of the people (2 m above the Earth's surface)

C_{M}=\frac{m_{p}55(10)^{9} kg (6370998 m)}{5.9(10)^{24} kg+55(10)^{9} kg}

C_{M}=5.9(10)^{-8} m This is the displacement of Earth's center of mass from the original center.

8 0
3 years ago
Two hockey players are about to collide on the ice, One player has a mass of
Furkat [3]

Answer:

19 kg x m/s East

Just did it!

3 0
3 years ago
At the start of a hockey game, the referee drops the puck between two players from opposing teams. Each player wants to push the
spin [16.1K]

Answer:

a) puck is subjected to both the forces of the hockey sticks in a horizontal direction,

b)the puck does not move since the sum of the forces is zero

c) changing the magnitude or direction of its applied force

Explanation:

a) The puck is subjected to both the forces of the hockey sticks in a horizontal direction, these forces are of equal magnitude and opposite direction since the puck is at rest.

In the direction of the y-axis (perpendicular to the ice) you have the weight of the disk and the normal to this weight that are also in equilibrium.

b) the puck does not move since the sum of the forces is zero, which implies that the forces of the hockey sticks are of equal magnitude and opposite direction.

c) the player has several ways to make the puck move

* slightly changing the angle of the club and therefore the direction of the force, in this case the disc comes out in the direction of this component

* inclined the stick slightly so that the force has a vertical component and the puck jumps in this direction

* Increasing the magnitude of the force so that the puck comes out in the opposite direction to the player

* The worst case, decreasing its force to zero and the disk comes out in its direction by the other force that had the same magnitude.

3 0
4 years ago
A tank is shaped like an upside-down square pyramid, with a base with sides that are 4 meters in length and a height of 12 meter
xeze [42]
Hello!

I included a link that might help you in terms of how the problem is broken down.

https://www.slader.com/discussion/question/a-tank-is-shaped-like-an-upside-down-square-pyramid-with-base-of-4m-by-4m-and-a-height-of-12m-how-fa/

However, the answer is:

The height increases at 3/2 m/sec
4 0
4 years ago
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