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Maslowich
3 years ago
15

What is the simplest relationship between the angular wavenumber k and just one of the other kinematic variables?

Physics
1 answer:
Inessa [10]3 years ago
6 0

Answer : k=\dfrac{\omega}{k}

Explanation :

The word kinematics means the study of motion. Kinematic variables gives the description of the motion of the body.

Displacement, Velocity, acceleration and time are associated with the motion of particle.

Wavenumber is defined as the frequency of wave, which is measured in cycles per unit distance.

Wave number is also defines as:

k=\dfrac{2\pi}{\lambda}

where, \lambda is wavelength

k=\dfrac{2\pi}{\lambda}\times \dfrac{T}{T}

since, \dfrac{2\pi}{T}=\omega \ and\ \dfrac{1}{V}=\dfrac{T}{\lambda}

So, k=\dfrac{\omega}{V}

Where, \omega is angular frequency and V is velocity of wave.

Hence, the  relationship between the angular wavenumber k and and kinamatic variable V is

k=\dfrac{\omega}{V}

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6) A pulsar is a rapidly rotating neutron star. The Crab nebula pulsar in the constellation Taurus has a period of 33.5 × 10−3 s
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a) L = 2.10x10⁴⁰ kg*m²/s

b) τ = 1.12x10²⁴ N.m

Explanation:

a) The angular momentum (L) of the pulsar can be calculated using the following equation:

L = I \omega

<u>Where:</u>

I: inertia momentum

ω: angular velocity

First we need to calculate ω and I. The angular velocity can be calculated as follows:

\omega = \frac{2 \pi}{T}

<u>Where:</u>

T: is the period = 33.5x10⁻³ s

\omega = \frac{2 \pi}{T} = \frac{2 \pi}{33.5 \cdot 10^{-3} s} = 187.56 rad/s

The inertia moment of the pulsar can be calculated using the following relation:

I = \frac{2}{5}mr^{2}

<u>Where</u>:

m: is the mass of the pulsar = 2.8x10³⁰ kg

r: is the radius = 10.0 km

I = \frac{2}{5}mr^{2} = \frac{2}{5}2.8\cdot 10^{30} kg*(10\cdot 10^{3} m)^{2} = 1.12 \cdot 10^{38} kg*m^{2}

Now, the  angular momentum of the pulsar is:

L = I \omega = 1.12 \cdot 10^{38} kg*m^{2}*187.56 rad/s = 2.10 \cdot 10^{40} kg*m^{2}*s^{-1}

b) If the angular velocity decreases at a rate of 10⁻¹⁴ rad/s², the torque of the pulsar is:

\tau = I*\alpha

<u>Where:</u>

α: is the angular acceleration = 10⁻¹⁴ rad/s²

\tau = I*\alpha = 1.12 \cdot 10^{38} kg*m^{2} * 10^{-14} rad*s^{-2} = 1.12 \cdot 10^{24} N.m

I hope it helps you!

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3 years ago
Consider two air-filled parallel-plate capacitors with circular plates. Capacitor 1 has a distance between plates d and plate ra
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Answer:

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Explanation:

The detailed and step by step calculation with the application of the appropriate formula is as shown in the attachment.

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