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2 years ago

An object started at

Physics

1 answer:

nataly862011 [7]2 years ago

5 0

Answer:

According to me, I think this is the answer

Explanation:

initial position= -22 meters.

this indicates that object is in the negative direction as a negative sign is used to represent the location.

displacement is indicated as -10.4 meters. this is also in the negative direction.

initial + displacement= final

= -22 + (-10.4)

= -32.4 meters

this would be the final position, away from the origin.

displacement is a vector quantity; both magnitude and direction matter.

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Determine if the data are qualitative or quantitative.

Amanda [17]

Answer:

Qualitative, Quantitative, Qualitative, Quantitative, and Qualitative.

Explanation:

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1 year ago

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Finger [1]

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3 years ago

A series of optical telescopes produced an image that has a resolution of about 0.00350 arc second.

Mila [183]

Answer:

The smallest diameter is $D =122 \ m$

Explanation:

From the question we are told that

The resolution of the telescope is $\theta = 0.00350 \ arc \ second$

The wavelength is $\lambda = 1.70 \mu m = 1.70 *10^{-6} \ m$

From the question we are told that

$1 arc \ sec = \frac{1}{3600^o}$

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Therefore

$x = 0.00350 * \frac{1}{3600 }$

$x = ( 9.722*10^{-7} )^o$

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So $(9.722*10^{-7})^o = \theta$

=> $\theta = (9.722*10^{-7}) * \frac{\pi}{180}$

$\theta = 1.69*10^{-8} rad$

The smallest diameter is mathematically represented as

$D = \frac{1.22 \lambda }{\theta }$

substituting values

$D = \frac{1.22 * 1.7 *10^{-6}} {1.69 *10^{-8} }$

$D =122 \ m$

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3 years ago

water in a cup and a kettle can have the same temperature even though the quantities are different . give reasons

jekas [21]

Answer:

The reason is because both are exposed to a virtually infinite heat sink, due to the virtually infinite mass and of the surrounding environment, compared to the sizes of either the cup or the kettle such that the equilibrium temperature, $T_{(equilibrium)}$ reached is the same for both the cup and the kettle as given by the relation;

$\infty M_{(environ)} \times c_{(environ)} \times (T_2 - T_1) = m_{1} \times c_{(water)} \times (T_3 - T_2) + m_{2} \times c_{(water)} \times (T_4 - T_2)$

Due to the large heat sink, T₂ - T₁ ≈ 0 such that the temperature of the kettle and that of the cup will both cool to the temperature of the environment

Explanation:

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3 years ago

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vredina [299]

Answer:

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3 years ago