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3 years ago

An object started at

Physics

1 answer:

nataly862011 [7]3 years ago

5 0

Answer:

According to me, I think this is the answer

Explanation:

initial position= -22 meters.

this indicates that object is in the negative direction as a negative sign is used to represent the location.

displacement is indicated as -10.4 meters. this is also in the negative direction.

initial + displacement= final

= -22 + (-10.4)

= -32.4 meters

this would be the final position, away from the origin.

displacement is a vector quantity; both magnitude and direction matter.

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Four mass–spring systems oscillate in simple harmonic motion. Rank the periods of oscillation for the mass–spring systems from l

liubo4ka [24]

The periods of oscillation for the mass–spring systems from largest to smallest is:

m = 4 kg , k = 2 N/m (T = 8.89 s)
m = 2 kg , k = 2 N/m (T = 6.28 s)
m = 2 kg , k = 4 N/m (T = 4.44 s)
m = 1 kg , k = 4 N/m (T = 3.14 s)

<h3>Explanation:</h3>

The period of oscillation in a simple harmonic motion is defined as the following formulation:

$T=2\pi \sqrt{\frac{m}{k} }$

Where:

T = period of oscillation

m = inertia mass of the oscillating body

k = spring constant

m = 2 kg , k = 2 N/m

$T=2\pi \sqrt{\frac{2}{2} }$

$T=2\pi$

T = 6.28 s

m = 2 kg , k = 4 N/m

$T=2\pi \sqrt{\frac{2}{4} }$

$T=2\pi \sqrt{\frac{1}{2} }$

T = 4.44 s

m = 4 kg , k = 2 N/m

$T=2\pi \sqrt{\frac{4}{2} }$

$T=2\pi \sqrt{2 }$

T = 8.89 s

m = 1 kg , k = 4 N/m

$T=2\pi \sqrt{\frac{1}{4} }$

$T=\pi$

T = 3.14 s

Therefore the rank the periods of oscillation for the mass–spring systems from largest to smallest is:

m = 4 kg , k = 2 N/m (T = 8.89 s)
m = 2 kg , k = 2 N/m (T = 6.28 s)
m = 2 kg , k = 4 N/m (T = 4.44 s)
m = 1 kg , k = 4 N/m (T = 3.14 s)

Learn more about simple harmonic motion brainly.com/question/13058166

#LearnWithBrainly

4 0

3 years ago

Read 2 more answers

You are given two vectors vector A = 4.9 at 31o vector B = 6 at 156o Angles are measured counterclockwise from the x-axis. What

Ket [755]

Answer:

C_{y} = 4.96 and θ' = 104,5º

Explanation:

To add several vectors we can decompose each one of them, perform the sum on each axis, to find the components of the resultant and then find the module and direction.

Let's start by decomposing the two vectors.

Vector A

sin θ = $A_{y}$ / A

cos θ = Aₓ / A

A_{y} = A sin θ

Ax = A cos θ

A_{y} = 4.9 sin 31 = 2.52

Ax = 4.9 cos 31 = 4.20

Vector B

B_{y} = B sin θ

Bx = B cos θ

B_{y} = 6 sin 156 = 2.44

Bx = 6 cos 156 = -5.48

The components of the resulting vector are

X axis

Cx = Ax + B x

Cx = 4.20 -5.48

Cx = -1.28

Axis y

C_{y} = Ay + By

C_{y} = 2.52 + 2.44

C_{y} = 4.96

Let's use the Pythagorean theorem to find modulo

C = √ (Cₙ²x2 + Cy2)

C = Ra (1.28 2 + 4.96 2)

C = 5.12

We use trigonemetry to find the angle

tan θ = C_{y} / Cₓ

θ’ = tan⁻¹ (4.96 / (1.28))

θ’ = 75.5

como el valor de Cy es positivo y Cx es negativo el angulo este en el segundo cuadrante, por lo cual el angulo medido respecto de eje x positivo es

θ’ = 180 – tes

θ‘= 180 – 75,5

θ' = 104,5º

7 0

3 years ago

A book with mass 2.3 kg sits on a table. What is the normal force on the

natita [175]

Explanation:

The table is level and there are no other forces on the book, so the normal force is equal to the weight.

N = mg

N = (2.3 kg) (9.8 m/s²)

N = 22.5 N

6 0

3 years ago

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If a statement is true, select true. if it's false, select false. <br>

Elena L [17]

3 is false 2 is true and the rest true

7 0

3 years ago

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A bicycle rider has a speed of 19.0 m/s at a height of 55.0 m above sea level when he begins coasting down hill. The mass of the

lukranit [14]

Answer:

The mechanical energy of the rider at any height will be 6.34 × 10⁴ J.

Explanation:

Hi there!

The mechanical energy of the rider is calculated as the sum of the gravitational potential energy plus the kinetic energy. Since there are no dissipative forces (like friction), the mechanical energy of the rider at a height of 55.0 m above the sea level will be the same at a height of 25.0 m (or at any height), because the loss in potential energy will be compensated by a gain in kinetic energy, according to the law of conservation of energy.

Then, calculating the potential and kinetic energy at 55.0 m and 19 m/s, we can obtain the mechanical energy that will be constant:

Mechanical energy = PE + KE

Where:

PE = potential energy.

KE = kinetic energy.

The potential energy is calculated as follows:

PE = m · g · h

Where:

m = mass of the object.

g = acceleration due to gravity.

h = height.

Then, the potential energy of the rider will be:

PE = 88.0 kg · 9.81 m/s² · 55.0 m = 4.75 × 10⁴ J

The kinetic energy is calculated as follows:

KE = 1/2 · m · v²

Where "m" is the mass of the object and "v" its velocity. Then:

KE = 1/2 · 88.0 kg · (19.0 m/s)²

KE = 1.59 × 10⁴ J

The mechanical energy of the rider will be:

Mechanical energy = PE + KE = 4.75 × 10⁴ J + 1.59 × 10⁴ J = 6.34 × 10⁴ J

This mechanical energy is constant because when the rider coast down the hill, its potential energy is being converted into kinetic energy, so that the sum of potential energy plus kinetic energy remains constant.

5 0

3 years ago