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scoray [572]
3 years ago
10

What is the total resistance for the circuit? (must include unit - ohms)

Physics
1 answer:
pochemuha3 years ago
3 0

Answer:

Total Resistance = 20 ohms

Explanation:

1/Rt = 1/R1 + 1/R2

1/Rt = 1/40 + 1/40

1/Rt = 1/20

Rt = 20

hope it helps!

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In a tug of war, when one team is pulling with a force of 85 N and the other 40 N, what is the net
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85 N - 40 N = 45 N
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The mass luminosity relation L  M 3.5 describes the mathematical relationship between luminosity and mass for main sequence sta
ivanzaharov [21]

Answer:

(a) <u>11.3 L</u>

(b) <u>10 M</u>

Explanation:

The mass-luminosity relationship states that:

Luminosity ∝ Mass^3.5

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L = Luminosity of Sun

M = mass of Sun

(a)

It is given that:

Mass of Star = 2M

Therefore, eqn (1) implies that:

Luminosity of star/L = (2M/M)^3.5

Luminosity of Star = (2)^3.5 L

<u>Luminosity of Star =  11.3 L</u>

(b)

It is given that:

Luminosity of star = 3160 L

Therefore, eqn (1) implies that:

3160L/L = (Mass of Star/M)^3.5

taking ln on both sides:

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3 0
3 years ago
Knowing Newton’s 2nd Law, how would you rearrange it to solve for acceleration.
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Answer:

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8 0
2 years ago
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Which of the following is true about a planet orbiting a star in uniform circular motion? A. The direction of the velocity vecto
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<span>As it is uniform circular motion therefore speed is constant. Therefore we can rule out option B. Also in circular motion the direction of velocity vector changes therefore velocity can't be constant. Therefore option B is incorrect as well. Also centripetal acceleration is always towards the center so option D is wrong as well. That implies option A is correct.</span>
4 0
3 years ago
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A 25-cm rod moves at 5. 0 m/s in a plane perpendicular to a magnetic field of strength 0. 25 t. the rod, velocity vector, and ma
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Length L = 25 cm = 0.25 m,  B = 600 G =  0.06 T ( 1G = 0.0001 T)

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Magnetic field

The magnetic influence on moving electric charges, electric currents, and magnetic materials is described by a magnetic field, which is a vector field. A force perpendicular to the charge's own velocity and the magnetic field acts on it when the charge is travelling through a magnetic field.

To learn more about the magnetic field refer here:

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