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Alla [95]
3 years ago
14

Which of the following are uses for radiation and radioactivity that are of benefit to us?

Chemistry
1 answer:
Kisachek [45]3 years ago
7 0
B. ii only

:) hope that helped
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TRUE or FALSE: The rock closest to the ridge is newer and younger than the older rock
alina1380 [7]

Answer:true

Explanation:

7 0
3 years ago
What is the freezing point of an aqueous 1.58 molal nacl solution?
Alina [70]
<span>Tf is the freezing point of the solution(the solvent plus solute). T*f is the freezing point of the pure solvent(without solute) i is the van't Hoff factor.It is approximately the number of particles in solution that are made for each particle of the solute that is placed into solution.Therefore, for nonelectrolytes, i = 1. Kf is the freezing point depression constant.For water, Kf = 1.86 Degree C/m, or 1.86 Degree C.kg/mol. Tf is -1.58 Degree C</span>
4 0
3 years ago
Which chemical class does phenobarbital belong to?
drek231 [11]
<span>Phenobarbital is derivative of Barbituric Acid and Barbituric Acid is derivative of Urea. (structures shown in Fig below)

Urea has H</span>₂N- group attached to Carbonyl Group (C=O), and such class of comounds conataining H₂N-C=O bond are called as Amides.

Result:
          So, <span>Phenobarbital belongs to Amides.</span>

3 0
3 years ago
4.5 × 1025 atoms of nickel equal how many moles?
sweet [91]
There should be 4.5 moles 
8 0
3 years ago
The mass of an unidentified rock is 40 grams. Students determine the volume of the rock by placing the rock in a cylinder with w
insens350 [35]

Answer:

A. Coal

Explanation:

Volume_{rock} = water displaced by rock

Water displaced by rock = volume of water after rock is dropped into the cylinder - volume of water before the rock was dropped into the water

Water displaced by the rock = 180 ml - 150 ml = 30 ml

Volume_{rock} = 30 ml

Density of rock:

40 grams => 30 ml

x grams => 1 ml

Cross multiply

1*40 = 30*x

40 = 30x

40/30 = 30x/30

1.3 = x

Density of rock = 1.3 g per 1 ml

Recall: 1 ml = 1 cm³

Therefore,

Density of the rock = 1.3 g/cm³

1.3 g/cm³ falls within the range of 1.1 - 1.4 g/cm³

Therefore, the rock is identified as Coal.

7 0
3 years ago
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