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sertanlavr [38]
3 years ago
8

How do the chemical properties of oxides change from left to right across a period? From top to bottom within a particular group

?
Chemistry
1 answer:
Advocard [28]3 years ago
4 0
From left to right going in the periodic table the oxides form basic oxide at left and becomes acidic at right the oxides at center are amphotreric by nature 
<span>like Na2O MgO are basic where As Cl2O7 SiO2 are acidic and ZnO etc are of dual nature that is they show both property of acidic and basic </span>
<span>some oxides are neutral </span>
<span>like CO </span>
<span>N2O </span>
<span>etc</span>
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In your own words, explain how you would make an electromagnet.
notsponge [240]

Electromagnets can be created by wrapping a wire around an iron nail and running current through the wire.
4 0
3 years ago
In the following reaction 6.13 g of water is actually produced, but the theoretical yield of water is 8.17 g. What is the percen
CaHeK987 [17]

Answer:

75.0%

Explanation:

Data obtained from the question. This includes the following:

Actual yield = 6.13g

Theoretical yield = 8.17g

Percentage yield =...?

The percentage yield can be obtain by using the following formula:

Percentage yield = Actual yield /Theoretical yield x 100

Percentage yield = 6.13/8.17 x 100

Percentage yield = 75.0%

Therefore, the percentage yield of water from the reaction above is 75.0%

3 0
3 years ago
The temperature of a sample of iron increased by 23.1 °C when 267 J of heat was applied. What is the mass of the sample?
hjlf

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25

Explanation:

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5 0
3 years ago
Read 2 more answers
The half-life of cobalt-60 is 5. 20 yr. how many milligrams of a 2. 000 mg sample remain after 6. 55 years?
Stels [109]

0.84 milligrams of a 2. 000 mg sample remain after 6. 55 years, according to radioactive decay.

Given data,

t\frac{1}{2} of Co-60 = 5.20years

amount of sample = 2.000mg initially = 0.002grams

According to radioactive decay,

N_{t} = N_{0}e^{-λt}

(N_{0} - 0.002 )λ = \frac{0.693}{t\frac{1}{2} } = \frac{0.693}{5.20}  = 0.133

According to radioactive decay,

N_{t} = N_{0}e^{-λt}

lnN_{t}  = lnN_{0} - λt

lnN_{t} = ln0.002 - (0.133×6.55)

       = -6.21 - 0.87 = -7.08 = 0.00084g = 0.84mg

Therefore, 0.84 milligrams of a 2. 000 mg sample remain after 6. 55 years.

Learn more about radioactive decay here:

brainly.com/question/1770619

#SPJ4

5 0
2 years ago
What is the molality of chloride ions in an aqueous solution of magnesium chloride for which xmgcl2 is 0.01?
AfilCa [17]
MgCl₂ ---> Mg(2+) + 2Cl(-)
0,01-x.............x.............2x

MgCl₂ ---> Mg(2+) + 2Cl(-)
0,01-x.............x.............2x
0...................0,01.......0,02

The molality of chloride ions is 0,02M.
8 0
4 years ago
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