Point A has the largest magnitude of acceleration as compared to other points on the position verses time graph.
On the graph, A is the point where magnitude of the acceleration of the particle is greatest as compared to other positions on the graph because the height of point A is the largest as compared to other points of the graph.
The graph shows at which point acceleration of an object is higher and lower so we can conclude that point A has the largest magnitude of acceleration as compared to other points on the position verses time graph.
Learn more about acceleration here: brainly.com/question/933224
Learn more: brainly.com/question/25887663
Answer:
She can swing 1.0 m high.
Explanation:
Hi there!
The mechanical energy of Jane (ME) can be calculated by adding her gravitational potential (PE) plus her kinetic energy (KE).
The kinetic energy is calculated as follows:
KE = 1/2 · m · v²
And the potential energy:
PE = m · g · h
Where:
m = mass of Jane.
v = velocity.
g = acceleration due to gravity (9.8 m/s²).
h = height.
Then:
ME = KE + PE
Initially, Jane is running on the surface on which we assume that the gravitational potential energy of Jane is zero (the height is zero). Then:
ME = KE + PE (PE = 0)
ME = KE
ME = 1/2 · m · (4.5 m/s)²
ME = m · 10.125 m²/s²
When Jane reaches the maximum height, its velocity is zero (all the kinetic energy was converted into potential energy). Then, the mechanical energy will be:
ME = KE + PE (KE = 0)
ME = PE
ME = m · 9.8 m/s² · h
Then, equallizing both expressions of ME and solving for h:
m · 10.125 m²/s² = m · 9.8 m/s² · h
10.125 m²/s² / 9.8 m/s² = h
h = 1.0 m
She can swing 1.0 m high (if we neglect dissipative forces such as air resistance).
Answer:
1.6 m/s^2
Explanation:
Hello!
To calculate the acceleration we must know the electric field. The electric field and the potential are related by:

If the particle starts at 2.3m, the electric field is:
E = 36.869 V/m = 36.869 N/C
So, the force on the particle is:
F = q E = 2.3×10^−6 C * 36.869 N/C = 8.48 x 10^-5 N
And its acceleration is :
a = F/m = 8.48 x 10^-5 N / 5.4×10−5 kg = 1.57 m/s^2
Rounded to two significant figures:
1.6 m/s^2
Seafloor spreading<span> is a process that </span>occurs<span> at mid-ocean ridges, where new oceanic crust is formed through volcanic activity and then gradually moves away from the ridge. </span>Seafloor spreading<span> helps explain continental drift in the theory of plate tectonics.
Hope this helps</span>