ANS
{ A }
Magnitude
Direction
{ B }
Average speed in ( m/s )
{ C }
Magnitude
Direction
A concave mirror forms a real image at 15.0 cm from the mirror surface along the principal axis. If the corresponding object is
1 answer:
Answer:
Focal length, f = 10 cm
Explanation:
We have,
A concave mirror forms a real image at 15.0 cm from the mirror surface along the principal axis, it means that the image distance is 15 cm
The object is placed at a distance of 30 cm, u = -30 cm
It is required to find the focal length of the mirror. Let it is f. Using mirror's formula to find it:
So, the focal length of the mirror is 10 cm.
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Answer:
Part A:
Part B:
Option B (Towards the South)
Explanation:
Part A:
Magnitude if electric field E:
E=Force/charge
Force=2.04×10−14 N
Charge=1.6×10−19 C
Part B:
Option B (Towards the South)
As electron is experiencing the force towards south,it means the direction of the electric field is towards the south because direction of field lines is from positive to negative, so proton is moving towards south it means negative charge is in south to which proton is attracted. So electric field is towards South.