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just olya [345]
3 years ago
8

A concave mirror forms a real image at 15.0 cm from the mirror surface along the principal axis. If the corresponding object is

at a distance of 30.0 cm, what is the mirror's focal length? Please show your work
Physics
1 answer:
kipiarov [429]3 years ago
6 0

Answer:

Focal length, f = 10 cm

Explanation:

We have,

A concave mirror forms a real image at 15.0 cm from the mirror surface along the principal axis, it means that the image distance is 15 cm

The object is placed at a distance of 30 cm, u = -30 cm

It is required to find the focal length of the mirror. Let it is f. Using mirror's formula to find it:

\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}\\\\\dfrac{1}{15}-\dfrac{1}{(-30)}=\dfrac{1}{f}\\\\f=10\ cm

So, the focal length of the mirror is 10 cm.

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Answer:

\frac{dV}{dt}=21.21cm^3/min

Explanation:

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3 years ago
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ikadub [295]
<h3>Answer:</h3>

225 meters

<h3>Explanation:</h3>

Acceleration is the rate of change in velocity of an object in motion.

In our case we are given;

Acceleration, a = 2.0 m/s²

Time, t = 15 s

We are required to find the length of the slope;

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<h3>Step 1: Calculate the final velocity, Vf</h3>

Using the equation of linear motion;

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Using the other equation of linear motion;

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We can calculate the length, S of the slope

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S = (0.5 × 2 × 15² ) - (0 × 15)

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3 years ago
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