Question in incomplete, complete question is:
Technetium (Tc; Z = 43) is a synthetic element used as a radioactive tracer in medical studies. A Tc atom emits a beta particle (electron) with a kinetic energy (Ek) of
. What is the de Broglie wavelength of this electron (Ek = ½mv²)?
Answer:
is the de Broglie wavelength of this electron.
Explanation:
To calculate the wavelength of a particle, we use the equation given by De-Broglie's wavelength, which is:

where,
= De-Broglie's wavelength = ?
h = Planck's constant = 
m = mass of beta particle = 
= kinetic energy of the particle = 
Putting values in above equation, we get:


is the de Broglie wavelength of this electron.
Answer:
They are eukaryotic, which means they have a nucleus. Most have mitochondria
Answer:
One that “Can be answered by conducting an experiment”
Explanation:
Answer:
Manganese
Explanation:
At Mass - No neutrons = Atomic Number = #protons in nucleus
47 - 22 = 25 => At. No. 25 is Manganese (Mn)