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3 years ago

The change of phase from a solid to a gas is called _____. evaporation melting sublimation vaporization

2 answers:

4 0

Solid to gas stage changes are known as "sublimation." In many cases, solids transform into gases simply after an intermediate liquid state. It is an endothermic procedure (happens with the absorption of heat from the environment).

Some example:

Freeze drying - Water can be sublimated in sustenance items by utilizing a vacuum.

"Dry ice" or, in other words carbon dioxide and as the name proposes it experiences stage change from solid state to liquid state straightforwardly without wetting or going into liquid state.

monitta3 years ago

4 0

The correct answer to the question is sublimation i.e the change of phase from solid to gas is called sublimation.

EXPLANATION:

Before answering the question, first we have to understand various changes of states of matter.

There are various state changes or phase changes in nature.

Melting: Melting is the heat phenomenon in which substance in solid phase is converted into liquid at its melting point. For instance, ice converted into water.

Sublimation: Sublimation is the type of phase change in which solid substance is directly converted into gas without melting. For instance, the vaporization of camphor.

Vaporization: Vaporization is the type of phase change of matter in which a liquid substance is converted into gas at its boiling point. For instance, boiling of water.

As per our question, the change is occurring from solid to gas.

Hence, the phase change will be sublimation.

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3. The electric field of a sinusoidal electromagnetic wave has an amplitude of 5.0 V/m. How much radiation energy passes through

True [87]

Answer:

e) $179$ J

Explanation:

$E_{o}$ = Magnitude of electric field = 5 V/m

$A$ = Area of window = 1.5 m²

$c$ = speed of electromagnetic wave = 3 x 10⁸ m/s

$\Delta t$ = time interval = 1 h = 3600 sec

radiation energy is given as

$U = (0.5)\epsilon _{o}E_{o}^{2}cA\Delta t$

$U = (0.5)(8.85\times 10^{-12})(5)^{2}(3\times 10^{8})(1.5)(3600)$

$U = 179$ J

6 0

3 years ago

A rock with a mass of 540 g in air is found to have an apparent mass of 342 g when submerged in water. (a) What mass of water is

AleksandrR [38]

(a) 198 g

When the rock is submerged into the water, there are two forces acting on the rock:

- its weight, equal to $W=mg$ (m=mass, g=acceleration of gravity), downward

- the buoyant force, equal to $B=m_w g$ ( $m_w$ =mass of water displaced), upward

So the resultant force, which is the apparent weight of the rock (W'), is

$W'=W-B$

which can be rewritten as

$m'g = mg-m_w g$

where m' is the apparent mass of the rock. Using:

m = 540 g

m' = 342 g

we find the mass of water displaced

$m_w = m-m'=540 g-342 g=198 g$

(b) $1.98\cdot 10^{-4} m^3$

If the rock is completely submerged, the volume of the rock corresponds to the volume of water displaced.

The volume of water displaced is given by

$V_w = \frac{m_w}{\rho_w}$

where

$m_w = 198 g = 0.198 kg$ is the mass of the water displaced

$\rho_w = 1000 kg/m^3$ is the density of the water

Substituting,

$V_w = \frac{0.198}{1000}=1.98\cdot 10^{-4} m^3$

And so this is also the volume of the rock.

(c) $2727 kg/m^3$

The average density of the rock is given by

$\rho = \frac{m}{V}$

where

m = 540 g = 0.540 kg is the mass of the rock

$V=1.98\cdot 10^{-4} m^3$ is its volume

Substituting into the equation, we find

$\rho = \frac{0.540 kg}{1.98\cdot 10^{-4}}=2727 kg/m^3$

3 0

3 years ago

Which planet has the most gravity and why

djyliett [7]

heya mate

the planet Jupiter has most gravity due to its size

7 0

3 years ago

Read 2 more answers

Explain why you can "stack" water slightly above the rim of a glass if you pour the water in very carefully?

jeka57 [31]

I believe Isaac Newtons Law " Gravity ".

8 0

3 years ago

At what height h above the ground does the projectile have a speed of 0.5v?

maw [93]

Answer:

$h=\dfrac{3v^2}{8g}$

Explanation:

It is given that,

Speed of the projectile is 0.5 v. Let h is the height above the ground. Using the first equation of motion to find it.

$v=u+at$

$v=u-gt$

Initial speed of the projectile is v and final speed is 0.5 v.

$0.5v=v-gt$

$t=\dfrac{v}{2g}$

g is the acceleration due to gravity

Let h is the height above the ground. Using the second equation of motion as :

$h=vt-\dfrac{1}{2}gt^2$

$h=v\dfrac{v}{2g}-\dfrac{1}{2}g(\dfrac{v}{2g})^2$

$h=\dfrac{3v^2}{8g}$

So, the height of the projectile above the ground is $\dfrac{3v^2}{8g}$ . Hence, this is the required solution.

6 0

3 years ago