To solve this problem we will use a free body diagram that allows us to determine the Normal Force.
In general, the normal force would be equivalent to
![N = mgcos\theta](https://tex.z-dn.net/?f=N%20%3D%20mgcos%5Ctheta)
Since the skier is standing on two skis, his weight will be divide by two
![N' = \frac{mgcos\theta}{2}](https://tex.z-dn.net/?f=N%27%20%3D%20%5Cfrac%7Bmgcos%5Ctheta%7D%7B2%7D)
Pressure is given as the force applied in a given area, that is
![P = \frac{F}{A}](https://tex.z-dn.net/?f=P%20%3D%20%5Cfrac%7BF%7D%7BA%7D)
Replacing F with N'
![P = \frac{N'}{A}](https://tex.z-dn.net/?f=P%20%3D%20%5Cfrac%7BN%27%7D%7BA%7D)
![P = \frac{\frac{mgcos\theta}{2}}{A}](https://tex.z-dn.net/?f=P%20%3D%20%5Cfrac%7B%5Cfrac%7Bmgcos%5Ctheta%7D%7B2%7D%7D%7BA%7D)
Our values are given as,
![m = 58kg](https://tex.z-dn.net/?f=m%20%3D%2058kg)
![g = 9.8m/s^2](https://tex.z-dn.net/?f=g%20%3D%209.8m%2Fs%5E2)
![\theta = 35\°](https://tex.z-dn.net/?f=%5Ctheta%20%3D%2035%5C%C2%B0)
![A = 0.3m^2](https://tex.z-dn.net/?f=A%20%3D%200.3m%5E2)
Replacing we have that
![P = \frac{\frac{(58)(9.8)cos(35)}{2}}{0.3}](https://tex.z-dn.net/?f=P%20%3D%20%5Cfrac%7B%5Cfrac%7B%2858%29%289.8%29cos%2835%29%7D%7B2%7D%7D%7B0.3%7D)
![P = 776.01Pa](https://tex.z-dn.net/?f=P%20%3D%20776.01Pa)
Therefore the pressure exerted by each ski on the snow is 776.01Pa
The formation of a cell plate is a characteristic of cytokinesis in terrestrial plants.
When the temperature of an object that is giving off light is increased, the particles in the object will move at a faster rate and there will be increased vibration of these molecules. This will makes the object to emit more light and to shine more brightly.
The acceleration of the jet is ![11.4 m/s^2](https://tex.z-dn.net/?f=11.4%20m%2Fs%5E2)
Explanation:
Since the jet motion is a uniformly accelerated motion (=constant acceleration), we can use the following suvat equation:
![v^2-u^2=2as](https://tex.z-dn.net/?f=v%5E2-u%5E2%3D2as)
where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the displacement
For the jet in this problem, we have
u = 0 (it starts from rest)
v = 40 m/s (final velocity)
s = 70 m (length of the runway)
Solving for a, we find the acceleration:
![a=\frac{v-u}{t}=\frac{40^2-0}{2(70)}=11.4 m/s^2](https://tex.z-dn.net/?f=a%3D%5Cfrac%7Bv-u%7D%7Bt%7D%3D%5Cfrac%7B40%5E2-0%7D%7B2%2870%29%7D%3D11.4%20m%2Fs%5E2)
Learn more about acceleration:
brainly.com/question/9527152
brainly.com/question/11181826
brainly.com/question/2506873
brainly.com/question/2562700
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