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notsponge [240]
4 years ago
11

Which kind of force do you exert on an object when you pull it toward you?

Physics
2 answers:
Vilka [71]4 years ago
7 0
It's gravity I believe? I'm not entirely sure.
riadik2000 [5.3K]4 years ago
4 0
You should expect applied force.

Hope this helps love!
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The distance between the centers of the wheels of a motorcycle is 156 cm. The center of mass of the motorcycle, including the ri
Drupady [299]

Answer:

a = 9.86 m/s²

Explanation:

given,

distance between the centers of wheel = 156 cm

center of mass of motorcycle including rider = 77.5 cm

horizontal acceleration of motor cycle = ?

now,

The moment created by the wheels must equal the moment created by gravity.

take moment about wheel as it touches the ground, here we will take horizontal distance between them.

then, take the moment around the center of mass. Since the force on the ground from the wheels is horizontal, we need the vertical distance.

now equating both the moment

m g d = F h

d is the horizontal distance

h is the vertical distance

m g d = m a h

term of mass get eliminated

g d = a h

so,

a = \dfrac{g\ d}{h}

a = \dfrac{9.8\times 0.78}{0.775}

a = 9.86 m/s²

4 0
3 years ago
How Many Days Would a Scientist Have To Wait For The Radioactivity To Be 12.5 The Starting Amount
kiruha [24]
They have to wait 18 days.
3 0
4 years ago
Read 2 more answers
A point charge that is exactly q =3 mu or micro CC is at the origin. In this problem, assume that the Coulomb constant k = 8.99
Simora [160]

Answer:

(a) V1 = 8990.00 V

V2 = 8960.13 V

Explanation:

Parameters given:

q =3 mC

k = 8.99 * 10⁹ Nm²/C²

x1 = 3 m

x2 = 3.01 m

Electric potential is given as:

V = kq/r

Where

k = Coulombs constant

q = charge

r = distance

Potential at x1 is:

V1 = (8.99 * 10⁹ * 0.000003)/(3)

V1 = 8990.00V

Potential at x2 is:

V2 = (8.99 * 10⁹ * 0.003)/(3.01)

V2 = 8960.13 V

7 0
3 years ago
Read 2 more answers
Astronomersestimatethata2.0-km-diameterasteroidcollides with the Earth once every million years. The collision could pose a thre
tangare [24]

Answer:

a) 1.6*10^21 Joules.

b) 40,000

Explanation:

part a )

maximum destructive energy that can be released is the case when all the kinetic energy of the asteroid is consumed.

therefore E = 1/2 m v^2

m= density * volume

= 3100* (4/3* pi * 1000^3 ) = 12978666666666.67 kg

given v = 16000m/s

therefore

E= 1/2 * 12978666666666.67 * 16000 * 16000

= 1.6 x 10^21 Joules!

part B)

each bomb is capable of 4 x 10^16 joules

therefore no of bombs that are needed to produce the required energy are

1.6 x 10^21 / 4 x 10^16 = 40,000

that is 40,000 such nuclear bombs are required!

7 0
3 years ago
Read 2 more answers
An inclined plane has a ramp length of 4.0 meters and a height of 2.0 meters. What is the IMA of the inclined plane? 0.5 2.0 6.0
Aleonysh [2.5K]

Length of the ramp (L) = 4.0 m = Distance traveled by the effort

Height of the inclined plane (h) = 2.0 m = Distance traveled by the resistance

IMA = Ideal mechanical advantage

IMA = \frac{L}{h}

IMA = \frac{4.0}{2.0}

IMA = 2.0

Hence, the IMA of the inclined plane is 2.0

6 0
3 years ago
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