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notsponge [240]
3 years ago
11

Which kind of force do you exert on an object when you pull it toward you?

Physics
2 answers:
Vilka [71]3 years ago
7 0
It's gravity I believe? I'm not entirely sure.
riadik2000 [5.3K]3 years ago
4 0
You should expect applied force.

Hope this helps love!
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Look at the graph.<br><br><br><br><br><br> If the price of peaches increases, what can be expected?
Fittoniya [83]
There will be less peaches soled
5 0
3 years ago
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A student standing on a stationary skateboard tosses a textbook with a mass of mb = 1.35 kg to a friend standing in front of him
nataly862011 [7]

Answer:

a) u_c=0\ m.s^{-1}       &        m_c.v_c=m_b.v_b\times \cos\theta

b) v_c=0.0566\ m.s^{-1}

c) p_e=2.9218\ kg.m.s^{-1}

Explanation:

Given:

mass of the book, m_b=1.35\ kg

combined mass of the student and the skateboard, m_c=97\ kg

initial velocity of the book, v_b=4.61\ m.s^{-1}

angle of projection of the book from the horizontal, \theta=28^{\circ}

a)

velocity of the student before throwing the book:

Since the student is initially at rest and no net force acts on the student so it remains in rest according to the Newton's first law of motion.

u_c=0\ m.s^{-1}

where:

u_c= initial velocity of the student

velocity of the student after throwing the book:

Since the student applies a force on the book while throwing it and the student standing on the skate will an elastic collision like situation on throwing the book.

m_c.v_c=m_b.v_b\times \cos\theta

where:

v_c= final velcotiy of the student after throwing the book

b)

m_c.v_c=m_b.v_b\times \cos\theta

97\times v_c=1.35\times 4.61\cos28

v_c=0.0566\ m.s^{-1}

c)

Since there is no movement of the student in the vertical direction, so the total momentum transfer to the earth will be equal to the momentum of the book in vertical direction.

p_e=m_b.v_b\sin\theta

p_e=1.35\times 4.61\times \sin28^{\circ}

p_e=2.9218\ kg.m.s^{-1}

6 0
3 years ago
How many joules of work are done against a truck when a force of 50 N pushes it 1 kilometer away
ELEN [110]

Answer:

Work = 50,000 J

Explanation:

Work = force * distance

Given that,

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Work = 50 * 1000

Work = 50,000 J

8 0
2 years ago
Two objects are moving at equal speed along a level, frictionless surface. the second object has twice the mass of the first obj
lbvjy [14]

Answer:

They both rises to same height.

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Now according to the question, two objects have same velocity but they have different masses.

Therefore, they rises to the same height because  height will not change with mass.

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Two people must have the same speed and velocity if
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If they both are moving with the same speed and direction
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