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Temka [501]
3 years ago
14

What is the slope of a line that is perpendicular to the x-axis?

Physics
1 answer:
hammer [34]3 years ago
7 0

That slope is called "undefined".  There's no number
that describes it.

If you take any two points on the line and try to use them
to calculate the slope, you'll wind up trying to divide by zero,
and that's not even allowed in arithmetic.

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What Type Of Technologies are helping reduce ozone?
atroni [7]

Sector-specific technological measures – vapor recovery nozzles at gasoline pumps, cleaner-burning fuels, strong vehicle inspection programs and strict emission limits for refineries, industrial emissions and combustion sources – all can help control ozone pollution and have contributed to lower emissions over the last three decades

hope this helps

4 0
3 years ago
A constant force of 5KN pulls a crate along a distance of 15 m in 75s.What is the power​
xxMikexx [17]

Explanation:

We know,

1KN = 1000N

Then, Force(F) = 5*1000N

=5000N

Here,

Power (P)=Work(W)/Time(T)

=Force * distance/ Time (W = F*s)

= 5000*15/75

=1000

So, The power of body or object is 1000Watt.

I hope this will be helpful for you.

8 0
4 years ago
14. The real risk-free rate of interest is 2%. Inflation is expected to be 3.5% the next 2 years and 6% during the next 3 years
Naddika [18.5K]

Answer:

3-year = 6.33%

5-year = 7%

Explanation:

Yield in security = Risk free rate + Maturity risk premium + Inflation premium + Liquidity premium + Default risk premium

Maturity risk premium is given as 0

Yield on 3-year treasury securities is 2 + [(3.5 + 3.5 + 6) / 3] + 0

= 6.33%

Yield on 5-year treasury securities is 2 + [(3.5 + 3.5 + 6 + 6 + 6) / 5] + 0

=7%

5 0
3 years ago
The pressure in an automobile tire is 198 kpa at 300.0 k. at the end of a trip on a hot, sunny day, the pressure has risen to 22
Kamila [148]

We can use the ideal gas equation which is expressed as PV = nRT. At a constant volume and number of moles of the gas the ratio of T and P is equal to some constant. At another set of condition, the constant is still the same. Calculations are as follows:

T1/P1 = T2/P2

T2 = P2 x T1 / P1

T2 = 225 x 300 / 198

<span>T2 = 340.91 K</span>

3 0
4 years ago
Imagine a particle that has three times the mass of the electron. All other quantities given above remain the same. What is the
melamori03 [73]

Answer:

The only parameter that changes is mass m

It is only necessary to calculate the ratio Eh/Ee

m_{h}=3m_{e}\\E_{h}=\frac{3m_{e}v^{2}}{2}\\E_{e}=\frac{m_{e}v^{2}}{2}\\\frac{E{h}}{E{e}}=3

The kinetic energy of the heavy paricle is three times the kinetic energy of an electron

5 0
4 years ago
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