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Temka [501]
3 years ago
14

What is the slope of a line that is perpendicular to the x-axis?

Physics
1 answer:
hammer [34]3 years ago
7 0

That slope is called "undefined".  There's no number
that describes it.

If you take any two points on the line and try to use them
to calculate the slope, you'll wind up trying to divide by zero,
and that's not even allowed in arithmetic.

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-Dominant- [34]
Potential energy U = mgh

Given h = 123 m,
mg = F = 780 N

Then
U = (123)(780)
= 95940
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3 years ago
The pictures below show a bottle made of plastic and a block made of concrete.
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3 years ago
Read 2 more answers
Suppose that the sound level of a conversation is initially at an angry 70 db and then drops to a soothing 50 db. assuming that
stepan [7]
Angry sound level = 70 db
Soothing sound level = 50 db
Frequency, f = 500 Hz
Assuming speed of sound = 345 m/s
Density (assumed) = 1.21 kg/m^3
Reference sound intensity, Io = 1*10^-12 w/m^2

Part (a): Initial sound intensity (angry sound)
10log (I/Io) = Sound level
Therefore,
For Ia = 70 db
Ia/(1*10^-12) = 10^(70/10)
Ia = 10^(70/10)*10^-12 = 1*10^-5 W/m^2

Part (b): Final sound intensity (soothing sound)
Is = 50 db
Therefore,
Is = 10^(50/10)*10^-12 = 18*10^-7 W/m^2

Part (c): Initial sound wave amplitude
Now,
I (W/m^2) = 0.5*A^2*density*velocity*4*π^2*frequency^2

Making A the subject;
A = Sqrt [I/(0.5*density*velocity*4π^2*frequency^2)]

Substituting;
A_initial = Sqrt [(1*10^-5)/(0.5*1.21*345*4π^2*500^2)] = 6.97*10^-8 m = 69.7 nm

Part (d): Final sound wave amplitude
A_final = Sqrt [(1*10^-7)/(0.5*1.21*345*4π^2*500^2)] = 6.97*10^-9 m = 6.97 nm
4 0
3 years ago
I throw a ball upward at an initial speed of 20 m/s. How much time does it take before the ball slows to a speed of 0 m/s
masha68 [24]
20/9.8 = 2.0 seconds. The ball stops after 2 seconds.
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What is the force of friction between the dragsters tires and the track if the dragster mass is 300kg and the coefficient of the
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Ff=μN=μmg=0.8*300*10=2400 N

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