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2 years ago

14

What is the slope of a line that is perpendicular to the x-axis?

1 answer:

hammer [34]2 years ago

7 0

That slope is called "undefined". There's no number
that describes it.

If you take any two points on the line and try to use them
to calculate the slope, you'll wind up trying to divide by zero,
and that's not even allowed in arithmetic.

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A coil of wire with 60 turns lies on the plane of the page, and a uniform magnetic field points into the page with a strength of

baherus [9]

Answer:

0.85V

Explanation:

The emf is calculated by using the Lenz's Law

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where we have taken that the intial time is t1=0

I hope this is useful for you

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2 years ago

When red-headed woodpeckers (melanerpes erythrocephalus) strike the trunk of a tree, they can experience an acceleration ten tim

kifflom [539]

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3 years ago

A projectile launcher has a mass of 3 kg. It fires a projectile of mass 0.08 kg horizontally at a speed of 300 m/s. a. What is t

alexdok [17]

Answer:

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Explanation:

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2 years ago

A person carries a plank of wood 1.6 m long with one hand pushing down on it at one end with a force F1 and the other hand holdi

Elis [28]

Answer: $115.52\ N$

Explanation:

Given

Length of plank is 1.6 m

Force $F_1$ is applied on the left side of plank

Force $F_2$ is applied 43 cm from the left end O.

Mass of the plank is $m=13.7\ kg$

for equilibrium

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$\Rightarrow mg\times 0.8-F_2\times 0.43=0\\\\\Rightarrow F_2=\dfrac{13.7\times 9.8\times 0.8}{0.43}\\\\\Rightarrow F_2=249.78\ N$

Net vertical force must be zero on the plank

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2 years ago

A string that passes over a pulley has a 0.341 kg mass attached to one end and a 0.625 kg mass attached to the other end. The pu

dalvyx [7]

Answer:

The frictional torque is $\tau = 0.2505 \ N \cdot m$

Explanation:

From the question we are told that

The mass attached to one end the string is $m_1 = 0.341 \ kg$

The mass attached to the other end of the string is $m_2 = 0.625 \ kg$

The radius of the disk is $r = 9.00 \ cm = 0.09 \ m$

At equilibrium the tension on the string due to the first mass is mathematically represented as

$T_1 = m_1 * g$

substituting values

$T_1 = 0.341 * 9.8$

$T_1 = 3.342 \ N$

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$T_2 = m_2 * g$

$T_2 = 0.625 * 9.8$

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The frictional torque that must be exerted is mathematically represented as

$\tau = (T_2 * r ) - (T_1 * r )$

substituting values

$\tau = ( 6.125 * 0.09 ) - (3.342 * 0.09 )$

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5 0

2 years ago